How do I programmatically print scope to a figure?

Hello,

I am trying to do what this button does from matlab

After some research in the online community, that is the only way I found to extract the data used by the scope to plot the lines, i.e. by getting the figure handles and looking into the axes children. Haven't found a way to do the same directly through the scope, which is why I am trying to copy the scope to a figure.

I found these set of commands online which does something similar,

% Get the name of the Scope of interest
scopeName = get_param(gcb,'Name');
% Find the Scope (which is really just a figure window)
hs = findall(0,'Name',scopeName);
% Create a new target figure
hf = figure('Position',get(hs,'Position'));
% Get the handle to the panel containing the plots
hp = findobj(hs.UserData.Parent,'Tag','VisualizationPanel');
% Copy the panel to the new figure
copyobj(hp,hf)

but the resulting figure no longer has the XY data when I try

findall(hf,'Type','line') or
findall(hf,'Type','stair')

Note that the above command works on the manually created figure (by clicking the 'Print to Figure' button)

Thanks

[Mathieu NOE]

hello

why not simply use a 'To Workspace' blocks in parallel to your Scope ?

then you have the data available in your workspace and you can move on from there

[Gaddiel Kamto]

That could certainly work.

The workflow I had begun was hinging on the first method of getting the data from figure directly, which is why I asked the question.

Not sure which would be more efficient though: adding/deleting 'To Workspace' blocks and processing the data in Workspace or extracting the data directly from the scopes/figures.

[Mathieu NOE]

why would you need to delete the 'To Workspace' blocks ?

[cr]

Just log the signals.