## Basic Function Error (Plot Related

on 23 Feb 2011

### Davide Ferraro (view profile)

y=f(x)=2.8x^3 - 3.5x^2 + 1.5x - (0.15 + 0.1*0.2529)=0
Plot this function (x in the range of [0, 1])
this is the given question following is my attempt
>> x=linspace(0,1,200);%this is to generate values for "x"
>> y=(2.8*x^3)-(-3.5*x^2)+(1.5*x)-(0.15+(0.1*stu_id))
??? Error using ==> mpower
Matrix must be square.
>> y=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))
??? y=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))
|
Error: Unexpected MATLAB operator.
>> y=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))=0
??? y=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))=0
|
Error: Unexpected MATLAB operator.
>> 0=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))
??? 0=(2.8*.x^3)-(-3.5*.x^2)+(1.5*.x)-(0.15+(0.1*stu_id))
|
Error: The expression to the left of the equals sign is not a
valid target for an assignment.
>>
much appreciate if anyone can point in the right direction

### Davide Ferraro (view profile)

on 23 Feb 2011

You should use the element by element power elevation ".^". Without the "dot" you are trying to do the power of a matrix and this is defined only for a square matrix.
y=(2.8*x.^3)-(-3.5*x.^2)+(1.5*x)-(0.15+(0.1*stu_id))
This should work to evaluate the function (you need also to define the stu_id variable).

buxZED

### buxZED (view profile)

on 23 Feb 2011
much appriciated :D

### Matt Tearle (view profile)

on 23 Feb 2011

The operator you're looking for is .^ (ie x.^2)
And similarly .* and ./