drawing a point in the graph

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Ismita
Ismita il 6 Dic 2022
Commentato: Ismita il 7 Dic 2022

Risposte (2)

Arif Hoq
Arif Hoq il 6 Dic 2022
Modificato: Arif Hoq il 6 Dic 2022
x = 1:5;
y = 20:24;
plot(x,y,x(3),y(3),'*') % specify a marker symbol * in index 3 of y
please follow this for more information about plot
  3 Commenti
Arif Hoq
Arif Hoq il 7 Dic 2022
try this approach. I am not sure about his efficiency.
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
[x1equality ia]=find(ismember(t1,t2));
[x3equality ib]=find(ismember(t3,t4));
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g',x1(ia),t1(ia),'*',x3(ib),t3(ib),'*')
Ismita
Ismita il 7 Dic 2022
Thank you :)

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Walter Roberson
Walter Roberson il 6 Dic 2022
x = 0:0.5:10;
t = (x/2).^2;
abs(x-2*sqrt(t)) %cross-check weether x == 2*sqrt(t)
ans = 1×21
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
plot(x, t, '*-')
  5 Commenti
Walter Roberson
Walter Roberson il 7 Dic 2022
plot(6.78233, 11.66, 'r*')
It does not matter if there is no exact match for this in the curves, if it is the correct intersection point.
Unless, that is, what you want to do is find the closest point on each of the two curves and mark those close points rather than the intersection point?
Ismita
Ismita il 7 Dic 2022
thank you :)

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