Maintain values inside loop

I need help debugging this part of my code, from annual data i want to create 12 timetables , one for each month. Right now the result shows only the last month (December), without keeping the previous ones.

for i =1:12
    resultsperMonth_=timetable(Datespermonth{i,1},dataperMonth{i,1})
end

Any ideas how to correct the above loop?

Answer 1

[Bora Eryilmaz]

Store the results in a vector of results instead of just keeping a scalar result for the last one. See the "{i}" index below:

for i = 1:12
    resultsperMonth_{i} = timetable(Datespermonth{i,1},dataperMonth{i,1})
end

You can do something like this:

A = {};
for i = 1:5
    A{i} = timetable;
end
A

A = 1×5 cell array
    {0×0 timetable}    {0×0 timetable}    {0×0 timetable}    {0×0 timetable}    {0×0 timetable}

[Ancalagon8]

Thanks for your reply. I have already tried this but I receive error: "Subscripting a table using linear indexing (one subscript) or multidimensional indexing (three or more subscripts) is not supported. Use a row subscript and a variable subscript."

[Bora Eryilmaz]

Then, you can use a cell array to store the results. I've updated the code above.

[Ancalagon8]

Thanks a lot!