how to convert z parameter to s parameter?

Hi,
I have two set of data.
One data has frequency, Z(ohm), theta.(R1Z.csv)
other data set has frequency, Z(db), theta (R1.txt)
I need to convert this two set of data from Z paramters to S parameter.
Could any one please help me to resolve the issue?

Risposte (1)

Depending on which way you want to go:
% Ohm to dB
Z = 4.17;
ZdB = 20 * log10(Z)
ZdB = 12.4027
% dB to ohm
ZdB = 12.39;
Z = 10^(ZdB / 20)
Z = 4.1639
I am not sure what you mean by S parameter, though.

4 Commenti

r= readmatrix('R3.txt','Delimiter',["\t",","],'TrimNonNumeric',true);
z1=r(:,2);
z2=r(:,3);
z=[z1 z2];
s_params=z2s(z,50);
Error using CheckNetworkData
Z_PARAMS must be a complex N-by-N-by-M array.
Error in z2s (line 17)
[m, z_params] = CheckNetworkData(z_params, 'N', 'Z_PARAMS');
Error in untitled5 (line 5)
s_params=z2s(z,50);
How to obatin S parameter from Z paramters?
The error "Z_PARAMS must be a complex N-by-N-by-M array." indicates that your variable z is not in the correct format. Is your z matrix a square matrix?
z = rand(3,3) + rand(3,3)*1i
z =
0.6536 + 0.5414i 0.9249 + 0.3064i 0.0514 + 0.9900i 0.4516 + 0.4830i 0.1859 + 0.3020i 0.1368 + 0.0369i 0.1193 + 0.5870i 0.8127 + 0.6790i 0.3449 + 0.4838i
z2s(z,5)
ans =
-0.7531 + 0.1247i 0.3522 + 0.0036i 0.0595 + 0.3156i 0.1718 + 0.1383i -0.9614 + 0.0743i 0.0721 - 0.0281i 0.0571 + 0.1417i 0.3157 + 0.1705i -0.8388 + 0.1480i
Okay is there a way to convert available data to to complex form?
Looks like to have magnitudes and angles as your data:
(1.23903195326879e+001dB,-8.89777753697489e+001°)
I think the right transformation to a complex format would be the (r,theta) to (x,y) transformation:
ZdB = 1.23903195326879e+001; % In dB
Z = 10^(ZdB / 20)
Z = 4.1641
thetaDeg = -8.89777753697489e+001; % In degrees
thetaRad = thetaDeg * pi / 180 % In radians
thetaRad = -1.5530
z = Z * (cos(thetaRad) + 1i*sin(thetaRad))
z = 0.0743 - 4.1634i
s = z2s(z, 1)
s = 0.8838 - 0.4504i
I don't know much about z2s transformations, so please double check if the last line gives you what you want.

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Richiesto:

il 20 Dic 2022

Commentato:

il 20 Dic 2022

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