# Can I change iteration value in following for loop?

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Jake il 21 Dic 2022
Commentato: Jan il 22 Dic 2022
Suppose I have the following code.
nf1 = 3; nf2 = 4;
panel_no = 1:12;
R_vx = rand(144,1);
for i = 1:nf1
for ii = 1:nf2
for iii = 1 : length(panel_no)
velx(iii,:, ii, i) = [panel_no(iii), R_vx(iii)];
end
end
end
velx
My goal is to create a 4D double matrix, and velx provides the right structure. However, it only includes the first 12 values of R_vx (for obvious reasons, of course). If the second iteration of the for loop starts from 13 for R_vx, and the third one from 25 and so on, I'd get the desired matrix. Is there a way to implement this? TIA!
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### Risposta accettata

Jan il 21 Dic 2022
Maybe you mean:
nf1 = 3; nf2 = 4;
panel_no = 1:12;
R_vx = rand(144,1);
velx = repmat([panel_no.', reshape(R_vx, 12, 12)], 1, 1, nf1, nf2);
It is hard to guess the wanted output based on a not working code.
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Jake il 22 Dic 2022
Yes! The bold guess works! :)
Introducing c was the missing link. Thank you so much!
Jan il 22 Dic 2022
@James: Fine. Then without a loop:
nf1 = 3; nf2 = 4;
panel_no = 1:12;
R_vx = rand(144,1);
A = [repmat(panel_no, 1, numel(R_vx)/numel(panel_no)); R_vx.'];
B = reshape(A, 2, 12, 4, 3);
C = permute(B, [2, 1, 3, 4]);

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