How can i delete max values for each 5 rows in vector

i have this vector A= 1 14 4 23 3 8 9 12 4 5 2 4 19 20 22

A=A'

The result will be R= 1 14 4 3 8 9 4 5 2 4 19 20

Answer 1

[Star Strider]

This looks like homework, however I need something to do this morning —

A = [1 14 4 23 3;     8 9 12 4 5;     2 4 19 20 22];

I = A<max(A,[],2);                                      % Logical Matrix

for k = 1:size(A,1)
    R(k,:) = A(k,I(k,:));                               % Loop  Necessary To Preserve Structure
end

R

R = 3×4

1 14 4 3 8 9 4 5 2 4 19 20

.

[abdullah al-dulaimi]

vector please don't convert to matrix

[Star Strider]

Now the transpose makes snese, with respect to ‘rows’.

Convert it to a matrix for the comparison, then back —

A= [1 14 4 23 3     8 9 12 4 5     2 4 19 20 22];
A = A.';
A = reshape(A,[],3);
for k = 1:size(A,2)
    R(:,k) = A(A(:,k)<max(A(:,k)),k);
end

R = R(:).'

R = 1×12

1 14 4 3 8 9 4 5 2 4 19 20

Answer 2

[Davide Masiello]

The following code will apply to any lenght of A and any length N of window from which to delete the maximum, provided that length(A)/N is an integer.

A = [1 14 4 23 3 8 9 12 4 5 2 4 19 20 22];
R = rmvMaxEveryN(A,5)

R = 1×12

1 14 4 3 8 9 4 5 2 4 19 20

function out = rmvMaxEveryN(array,N)
[~,idx]    = max(reshape(array,[N,length(array)/N]),[],1);
idx        = idx+(0:N:length(array)-N);
array(idx) = [];
out        = array;
end

[abdullah al-dulaimi]

؟

[abdullah al-dulaimi]

check the results above

[Davide Masiello]

Sorry I realised later there was a mistake and adjusted my answer.