Azzera filtri
Azzera filtri

finding a number in the vector equal or around a desired number

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I am trying to the from dleta_A vector a number equal to 3.1528 or two numbers rounded up and down for the desired number
V_breadth = 12;
d_Vd = 0:0.005:2;
V_Draft_min = 0.5;
V_breadth_min = 0.4*V_breadth;
V_breadth_max = 0.8*V_breadth;
for i = 1:1:length(d_Vd)
V_Draft_new(i) =V_Draft_min+ d_Vd(i);
tan_theta = (V_Draft - V_Draft_min )/(0.5*(V_breadth_max-V_breadth_min));
Vb(i) = V_breadth_min + (d_Vd(i).*(2/tan_theta));
dleta_A(i) = (V_breadth_min+ Vb(i)) *d_Vd(i)/2;
end
V_Draft_new
Vb
dleta_A

Risposta accettata

Image Analyst
Image Analyst il 30 Dic 2022
Try this
% Create sample data
dleta_A = 4 * rand(1, 1000)
dleta_A = 1×1000
1.3165 0.9536 1.6464 3.0427 3.4164 2.8714 2.8714 1.5470 3.9519 3.3921 2.2466 3.1289 2.5613 3.5461 3.0159 3.7663 3.6834 1.4579 3.4715 1.1341 3.1148 3.3452 2.9969 0.6242 2.5960 3.9745 2.0811 1.2933 0.1543 1.7560
% Find element of dleta_A that is closest to 3.1528.
differences = abs(dleta_A - 3.1528);
[minDifference, indexOfMin] = min(differences)
minDifference = 0.0022
indexOfMin = 871
closestValue = dleta_A(indexOfMin)
closestValue = 3.1550

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