Azzera filtri
Azzera filtri

how to get this right?

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riki singh
riki singh il 10 Gen 2023
Commentato: Walter Roberson il 10 Gen 2023
x = rand(30) * 25;
y = rand(30) * -28;
z = complex(x, y);
Z=ifft2(z);
Z = ifft2(y,8,8);
Z=size(Z);
is it possible to convert 2 D matrix into 3 D matrix ?
once i get 3D matrix
then
A(a,b,c)=Z
a=(x^2+y^2+2*z)/2*x;
so now i want Z terms which is in Z(x,y,z) terms into A(a,b,c)
2021a version
  1 Commento
Walter Roberson
Walter Roberson il 10 Gen 2023
Z=ifft2(z);
Z = ifft2(y,8,8);
Z=size(Z);
why do you overwrite the first Z calculation with the results of a different ifft2? And why do you overwrite the results of that with the size of the second ifft2?

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