Hi, I am trying to produce randomly circles with same radius in defined range or square. I wrote the code, but it show error " Out of memory. The likely cause is an infinite"

function h = circle(x,y,r, N)
%INPUT
%x= range of x
%y= range of y 
%OUTPUT
% circles between x and y range with same radious
hold on
x=[0 10];
y=[0 10];
r=5;
N=5;
for i=1:1:N
    while 1
        x1=min(x)+(max(x)-min(x))*rand(1);
        y1=min(y)+(max(y)-min(y))*rand(1);
        
        th = 0:pi/50:2*pi;
        x2 = r * cos(th) + x1;
        y2 = r * sin(th) + y2;
        
        for i=1:1:size(circle)
            
            x1=circle(i,1);
            y1=circle(i,2);
            x2=circle(i,3);
            y2=circle(i,4);
            h = plot([x1, y1],[x2, y2], "b");
            
            pos = [min(x1,x2) min(y1,y2) abs(x2-x1) abs(y2-y1)];
            rectangle('Position',pos,'Curvature',[1 1]);
        end
    end
end 
hold off

Answer 1

[Walter Roberson]

function h = circle(x,y,r, N)
...
for i=1:1:size(circle)

circle is not a local variable in the function circle, and is not the target of an import statement. Therefore the reference to size(circle) is a request to execute the function circle with no parameters, and when that call eventually returns, to return a vector of the size of the return value of the function circle. The return value of size() is always at least two values. You are using that vector with the : operator. When you use a non-scalar with a : operator, then the effect is the same as taking only the first value in the array.

So that section of code is equivalent to

   temporary_variable = circle();                    %call circle
   temporary_variable2 = size(temporary_variable);   %take the size of what circle() returned
   for i = 1 : 1 : temporary_variable2(1)

and in turn that would be equivalent to

  temporary_variable = circle();                    %call circle
  for i = 1 : 1 : size(temporary_variable,1)

So what is this function circle that needs to be executed in order to discard its output other than to take the number of rows of the output? Why, circle is the very function that you are executing. So the function circle cannot finish executing to return a value until the function circle finishes executing (which cannot finish until the function circle() finishes executing, which cannot finish until....)