problem with code

I am trying a script that does not work. First I define a structure in matlab:
>> package=struct('item_no',123,'cost',19.99,'price',39.95,'code','g')
package =
item_no: 123
cost: 19.9900
price: 39.9500
code: 'g'
then I have made a script who will try to find out the value of a field in the structure:
inputfield=input('Which field would you like to see: ','s')
if isfield(package, inputfield)
fprintf('The value of the %s field is: %c\n',inputfield,...
eval(['package.'inputfield]))
else
fprintf('Error: %s is not valid field\n', inputfield)
end
but i get error message:
>> structurevalue ??? Error: File: structurevalue.m Line: 6 Column: 22 Unexpected MATLAB expression.

 Risposta accettata

Mitch Martelli
Mitch Martelli il 22 Ott 2011

0 voti

the problem is in the eval,try to put a blank after 'package.' :
eval(['package.' inputfield])

5 Commenti

Tor Fredrik Hove
Tor Fredrik Hove il 22 Ott 2011
Thanks for both answers!
I have added a space and it works except one problem. When I want value for item_no it does not give right information:
>> package=struct('item_no',123,'cost',19.99,'price',39.95,'code','g')
package =
item_no: 123
cost: 19.9900
price: 39.9500
code: 'g'
>> structurevalue
Which field would you like to see: cost
inputfield =
cost
The value of the cost field is: 1.999000e+001
>> structurevalue
Which field would you like to see: item_no
inputfield =
item_no
The value of the item_no field is: {
>>
the script again with only an extra space added:
inputfield=input('Which field would you like to see: ','s')
if isfield(package, inputfield)
fprintf('The value of the %s field is: %c\n',inputfield,...
eval(['package.' inputfield]))
else
fprintf('Error: %s is not valid field\n', inputfield)
end
Mitch Martelli
Mitch Martelli il 22 Ott 2011
you have right...
eval(package.item_no)
return the corresponding ASCII symbol because the argoument is integer
Image Analyst
Image Analyst il 22 Ott 2011
I'm not sure why you accepted this answer instead of my answer, or why Mitch even offered this answer, since my answer was posted previously here. I believe my answer is the preferred method, as I often see other experts recommend for dynamic field names and against eval. If you still plan on using eval, you should read the FAQ: http://matlab.wikia.com/wiki/FAQ#Why_is_it_advised_to_avoid_using_the_.22eval.22_function.3F
Tor Fredrik Hove
Tor Fredrik Hove il 22 Ott 2011
Hi Image Analyst! I am a bit new with matlab so convenient choices is not my strong side. Eval is also a part of the curriculum so I have to know something about it either way
Jan
Jan il 22 Ott 2011
I do not understand what "is part of the curriculum" means. Using EVAL is a bad programming practize, because it is prone to errors and results in slow code.
"package.(inputfield)" is much safer and faster than "eval(['package.' inputfield])".

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Più risposte (1)

Image Analyst
Image Analyst il 22 Ott 2011

1 voto

This is what the line should look like:
fprintf('The value of the %s field is: %c\n',inputfield, package.(inputfield));
Look up "dynamic field names" in the help for more info.

1 Commento

Jan
Jan il 22 Ott 2011
+1: Best answer. Perhaps ignoring your answers is a running joke. However, I'm missing the punchline.

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