Matlab Transfer function multiple single s terms
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Aaron Frost
il 20 Feb 2023
Commentato: Paul
il 22 Feb 2023
How can modify this script in order to get the transfer function shown in the picutre. Thanks.
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
A = 1/(C1*R2);
B = 1/(C2*R2);
C = (1/(C1*R1))*(1-G);
D = 1/(C1*C2*R1*R2);
G = (R3+R4)/R3;
%{
Numerator = {[G 0 0] };
Denominator = {[1 0] [A] [B] [C] [0 D]};
T = tf(Numerator, Denominator)
%}
T = tf([G 0 0], {[1] [A] [B] [C] [0 D]})
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Risposta accettata
Sulaymon Eshkabilov
il 20 Feb 2023
Here it is:
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
G = (R3+R4)/R3;
A = 1/(C1*R2);
B = 1/(C2*R2);
C = (1/(C1*R1))*(1-G);
D = 1/(C1*C2*R1*R2);
%{
Numerator = {[G 0 0] };
Denominator = {[1 0] [A] [B] [C] [0 D]};
T = tf(Numerator, Denominator)
%}
T = tf([G 0 0], [1 (A+B+C) -D])
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Più risposte (1)
Walter Roberson
il 20 Feb 2023
syms G C_1 R_2 C_2 R_1 s R_3 R_4
G = (R_3 + R_4)/R_3
vratio = G*s^2/ ( s^2 + s * (1/(C_1*R_2) + 1/(C_2*R_2) + 1/(C_1*R_1)*(1-G)) + 1/(C_1*C_2*R_1*R_2) )
vex = expand(vratio);
[N, D] = numden(vex)
Nc = collect(N, s);
Dc = collect(D, s);
vpretty = Nc/Dc
NCs = coeffs(Nc, s, 'all')
DCs = coeffs(Dc, s, 'all')
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
NC = double(subs(NCs, [C_1, C_2, R_1, R_2, R_3, R_4], [C1, C2, R1, R2, R3, R4]));
DC = double(subs(DCs, [C_1, C_2, R_1, R_2, R_3, R_4], [C1, C2, R1, R2, R3, R4]));
leading = DC(1);
NC = NC ./ leading;
DC = DC ./ leading;
sys = tf(NC, DC)
2 Commenti
Walter Roberson
il 21 Feb 2023
Note that the reason to solve symbolically is to construct a general form that multiple sets of resister and capacitor values could be substituted into. After calculating NCs and DCs you could use matlabFunction() to create functions that would accept numeric inputs and calculate the coefficients.
Paul
il 22 Feb 2023
But the CST can handle this directly without too much complication, even if the desire is to have a general expression
s = tf('s');
G = @(R_3,R_4) ((R_3 + R_4)/R_3);
vratio = @(C_1,C_2,R_1,R_2,R_3,R_4) G(R_3,R_4)*s^2/ ( s^2 + s * (1/(C_1*R_2) + 1/(C_2*R_2) + 1/(C_1*R_1)*(1-G(R_3,R_4))) + 1/(C_1*C_2*R_1*R_2) );
C1 = 0.000000000150;
C2 = 0.000000000470;
R1 = 10000;
R2 = 180000;
R3 = 2700;
R4 = 56000;
vratio(C1,C2,R1,R2,R3,R4)
Unrelated comment, but I have my suspicions about the expression for vratio in the question. I thought that circuits composed of just (positive) resistors and (positive) capacitors can't be unstable, whereas vratio clearly is.
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