Keep pairs of corresponding elements in 2 vectors based on conditions
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I have the problem here: Using this image below: I want to check for several conditions
the orange and green marks are annotations on a signal. If we consider vectors orange, and green which contain the points needed to make the annotations.
The point is to have perfect pairs and ignore all others. i.e. orange(i) and green(i) is a pair if orange(i)<green(i)
so all values in vector orange are lower than their corresponding elements in vector green.
I want to check the following conditions.
I started but some conditions dont work, thats why i need help.
Condition 1: orange must always begin, so if a green begins I delete that green point. [done]
condition 2: if 2 or more greens come before an orange, delete all unecessary green to keep a pair.
condition 3: similarly if several orange exist delete them to keep a pair.
so in the end I want to have a perfect system of pairs, where orange starts a pair. like this:
orange=[212929;213223;213482;213740;214013;214790];
green= [212765;213301;213822;214090;214240;214426;214941];
if green(1)<orange(1)
green=green(2:end);
end
lenss =min(length(orange),length(green));
i = 1;
while i <= lenss
if abs(green(i)-orange(i)) <0
green(i) = [];
i=1;
continue;
else
i=1+1;
continue;
end
end
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Jan
il 14 Mar 2023
Modificato: Jan
il 14 Mar 2023
orange = [212929;213223;213482;213740;214013;214790];
green = [212765;213301;213822;214090;214240;214426;214941];
[x, s] = sort([orange.', green.']);
index = strfind(s <= numel(orange), [true, false]);
ok_orange = x(index)
ok_green = x(index + 1)
The idea: sort all elements. If their sorting index is greater than the number of orange elements, they are green. So s <= numel(orange) is a logical vector, which is TRUE for orange and FALSE for green. Now find the neighboring [true, false] pairs.
5 Commenti
Dyuman Joshi
il 16 Mar 2023
Modificato: Dyuman Joshi
il 16 Mar 2023
Wow, just shy of my time on this planet!
What prompted you to try out MATLAB at that time and to stick with it for so long and continue using it? (If you don't mind me asking)
(I feel like this would be an interesting conversation to have with the MATLAB Answers community!)
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