How to generate joint frequency table?

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Dear experts,
I have two vectors and I want to make a joint frequency table, I tried tabulate but failed, I was wondering what is wrong with my code, and if there is any other code can help me do this?
Many thanks!
Below is the code I tried:
% Two vectors
Attribute
Assignment_result
% Combine them together
data=table(Attribute,Assignment_result)
% Tabulate
joint_freq=tabulate(data.Attribute,data.Assignment_result)
disp(joint_freq)
But matlab suggests 'too many input arguments'
  3 Commenti
Dyuman Joshi
Dyuman Joshi il 12 Apr 2023
tabulate() accepts only 1 input, whereas you are giving 2 inputs to it.
What are you trying to do? Calculating the frequency of 1 vector w.r.t to other?
In any case, please attach your data (use the paperclip icon to do so), and mention the output you want to obtain.
Rouyu Chen
Rouyu Chen il 12 Apr 2023
Thank you Jon and Dyuman Joshi!

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the cyclist
the cyclist il 12 Apr 2023
It isn't perfectly clear what you mean, but I think this does what you intend.
% Set the seed, for reproduciblity
rng default
% Two example vectors
vector1 = randi([1, 3], 5, 1);
vector2 = randi([1, 3], 5, 1);
% Combine the vectors into a matrix
data = [vector1, vector2]
data = 5×2
3 1 3 1 1 2 3 3 2 3
% Unique rows and their indices
[unique_rows, ~, row_indices] = unique(data, 'rows');
% Frequency of each unique row
freq = histcounts(row_indices, 1:size(unique_rows,1)+1);
% Combine the unique rows and their frequencies into a table
freq_table = table(unique_rows, freq', 'VariableNames', {'UniqueRows', 'Frequency'})
freq_table = 4×2 table
UniqueRows Frequency __________ _________ 1 2 1 2 3 1 3 1 2 3 3 1
  3 Commenti
the cyclist
the cyclist il 12 Apr 2023
Ah, you want a cross table:
% Set the seed, for reproduciblity
rng default
% Two example vectors
vector1 = randi([1, 3], 5, 1);
vector2 = randi([1, 3], 5, 1);
[tbl,chi2,p,labels] = crosstab(vector1,vector2)
tbl = 3×3
0 1 0 0 0 1 2 0 1
chi2 = 6.6667
p = 0.1546
labels = 3×2 cell array
{'1'} {'1'} {'2'} {'2'} {'3'} {'3'}
Rouyu Chen
Rouyu Chen il 12 Apr 2023
This is exactly what I am looking for, thank you so much!

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