# Create a new vector to set identity of each cell in Voronoi Diagram

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Mst Shanta il 29 Apr 2023
Hi,
I have two vectors X and Y, which create voronoi diagram. I will have to represent three types of cells (S, L and R) in the voronoi tessellation. To that end, I will have to generate another vector say C, which will set the identity of each voronoi cell i.e. three types of cells in the lattice.
For instance, X=[ 1.344 Y=[4.3301 C=[ 0
2.331 -1.2204 1
-2.194] 2.3210] 2]
where, 0 means 'S' cells, 1 means 'L' cells and 2 means 'R' cells or something like that.
Can anyone please help me to create a vector C, which will set the identity of each cell?
Actually, in a column vector, I will have to design like these data points are for these types of cells and these data points are for these types of cells (like S, L, R) and then show those distinct types of cells in the diagram.
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### Risposte (1)

Scott MacKenzie il 1 Mag 2023
Modificato: Scott MacKenzie il 2 Mag 2023
If I understand correctly, C -- the type of each cell -- identifies the corresponding quadrant for each point. You also want to show each type in the diagram. Here's a script to do this using a different fill color for each cell type:
load test_data % load X and Y (data in script posted in question)
% compute C to identify each cell as S, L, or R, as in question
S = X >= 0 & Y >= 0;
L = X > 0 & Y < 0;
R = X < 0 & Y > 0;
C = 0*S + 1*L + 2*R;
% get voronoi verticies (v) and cells (c) for data set
[v, c] = voronoin([X Y]);
% create basic voronoi figure from data in question
voronoi(X,Y);
axis([-4.1 4.1 -4 4]);
% color the cells to show type
hold on;
for i=1:length(X)
% get verticies of next polygon
px = v(c{i},1);
py = v(c{i},2);
% choose a color, as per cell type
switch C(i)
case 0
clr = [.9 .8 .7]; % S
case 1
clr = [.7 .8 .9]; % L
case 2
clr = [.8 .7 .9]; % R
end
% fill the polygon to show cell type
fill(px, py, clr, 'FaceAlpha', 0.5);
end
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