Matlab 2013a and Excel

1 visualizzazione (ultimi 30 giorni)
Marcos Tawadros
Marcos Tawadros il 2 Apr 2015
Commentato: Marcos Tawadros il 28 Apr 2015
I am using Matlab 2013 a and I have an excel sheet that has 2D numerical values. For e.g:
-3 -2 -1 0 1 2 3
0 2.1 5 4 2.5 3 8 9
-1 11 12 13 9 4 2 1
and so on, I would like to know how I can get a certain cell value such as '13' as an e.g. from the values (-1,-1), what function i can use and how. thanks in advance.
  5 Commenti
per isakson
per isakson il 3 Apr 2015
Never write "not working" without telling in what way and providing an error message.
data seems to be a row vector. What does
whos data
show?
Marcos Tawadros
Marcos Tawadros il 28 Apr 2015
how can I plot these data plot(z,x,Bt) ????

Accedi per commentare.

Risposte (2)

per isakson
per isakson il 2 Apr 2015
Assumption:
  • the values in the top row are unique integers
  • the values in the leftest column are unique integers
Hint:
data = [ 2.1 5 4 2.5 3 8 9
11 12 13 9 4 2 1 ];
row_points = [ 0; -1 ];
col_points = [ -3 -2 -1 0 1 2 3 ];
data( row_points==-1, col_points==-1 )
returns
ans =
13
  8 Commenti
Marcos Tawadros
Marcos Tawadros il 3 Apr 2015
I know the output is gonna be a scalar integer 1*1.
Marcos Tawadros
Marcos Tawadros il 28 Apr 2015
how can I plot(data(row_points,column_points) with row_points and column_points?

Accedi per commentare.


LUI PAUL
LUI PAUL il 3 Apr 2015
if this is your excel data(say)
-3 -2 -1 0 1 2 3
0 2.1 5 4 2.5 3 8
-1 11 12 13 9 4 2
num = xlsread('cloudy.xlsx');
value=num(2,2); %for value Of B2 in excel
the value will be 2.1
  2 Commenti
Marcos Tawadros
Marcos Tawadros il 3 Apr 2015
Subscripting into an mxArray is not supported.
LUI PAUL
LUI PAUL il 5 Apr 2015
please clarify your comment

Accedi per commentare.

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by