error using horzcat function
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Very simple code of adding two matrices horizontally retyrns an error using horzcat, dimensions of arrays being concatenated are not consistent. the error is on line (theta = [theta(:,1:6),zeros(length(theta),1)];).
the excel file has a matrix of 4x6, which i check with size theta even.
the code is:
clear all
clc
% Input:
tmp = importdata ('exp.xlsx');
theta = tmp.data;
theta = [theta(:,1:6),zeros(length(theta),1)];
% Calcu
theta (:,7) = theta (:,2).*theta(:,3);
%output
file_name = 'total.txt';
fid = fopen(file_name,'w');
fprintf(fid,'This file is written by matlab code.\n\n');
fprintf(fid,'This code will calculate the total.\n\n');
for i = 1:length(theta)
fprintf(fid,'The total of %d with age %f and exp %f is %f.\n',theta(i,1),theta(i,2),theta(i,3),theta(i,4));
end
fprintf(fid,'\nENDFILE');
fclose (fid);
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VBBV
il 14 Giu 2023
Modificato: VBBV
il 14 Giu 2023
theta = [theta(:,1:6),zeros(size(theta,1),1)];
4 Commenti
Steven Lord
il 14 Giu 2023
The length function on a non-empty array returns the size in the longest dimension of your array. That's not necessarily the number of rows.
A = ones(3, 6);
length(A)
Calling size with 1 as the dimension input will give you the number of rows in the array.
size(A, 1)
Più risposte (1)
Satwik
il 14 Giu 2023
You can make the following change if your goal is to concatenate.
tmp = zeros(4,6);
theta = tmp;
theta = [theta(:,1:6),zeros(size(theta,1),1)]
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