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Programming in MATLAB applied to interdisciplinary engineering fields

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Answered
Error using / Arguments must be numeric, char, or logical.
y=@(t) 2.718.^(-t/5)-(2.718.^(-t/5).*t)/5; t=0:1:10; plot(t,y(t)) Define the equation as anonymous function and plot

3 giorni ago | 0

Answered
Bar plot with two x axis and Display Groups of Bars
x = 2010:2019; y = rand(1,10); % 1 y6= rand(1,10); % 2 yyaxis left %ax = gca; %ax.YAxis.Exponent = 2; b = bar(x,[y;y6]);...

4 giorni ago | 0

Answered
Not enough input argument in ode45
[t,x] = ode45(@mastersystem,[0 10],[0 0 0 0 0 0]); % use a function handle to pass function as argument plot(t,x) function d...

4 giorni ago | 0

Answered
What's wrong with my distribution function?
X = -100 : 1 : 100; Y = -100 : 1 : 100; k = 4; G = gamma(k/2) [ XX, YY ] = meshgrid( X, Y ); A = ( XX ).^2 + ( YY ).^2; A ...

5 giorni ago | 1

Answered
Plot measured Filter data
T = readtable('Plot.xls') frequency = T{(22:109),1}; % change this to ffequency gain = T{(22:109),2}; phase = T{(22:109),...

5 giorni ago | 0

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Answered
matlab indexing issue with range -pi:pi
amin=0.2; theta = -pi:pi/2:pi; gamma=0:0.5:3; for T=1:length(theta) for G = 1:length(gamma) phi=amin-(-pi/2); ...

6 giorni ago | 0

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Answered
phase shift using xcorr
t = 1 :0.1: 20; phaseshift= pi/2; s1 = sin(2*t); s2 = sin(2*t+ phaseshift); figure(1); clf; plot (t...

9 giorni ago | 0

Answered
I am trying to find the integral gain (ki) of the following transfer function.
syms ki ki = 10 % e.g numeric values , not symbolic sys = tf([30.672 175.694*ki],[1 38.672 175.694*ki]); S = stepinfo(sys); ...

9 giorni ago | 0

Answered
Hold on with subplot in a loop
A={[40;50;60] [70;80;90] [20;30;50]}; B={[45;55;65] [75;85;95] [25;35;55]}; T=[1;2;3]; figure(1) % use this outside of l...

10 giorni ago | 0

Answered
Question about the inability to display 16k octave bands(1/3 oct band)?
if fs==22050 fc=1000*2.^((-6:1:2)); fctxt={'16','32','63','125','250','500','1k','2k','4k'}; else fc=1000*...

11 giorni ago | 1

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Answered
Error using FDE12
s = 1:4; % define s vector passed as argument to function line below e.g. values sdot = @(t,s)[A-(e*s(1)*s(2))-(a*s(1)*s(3))+...

12 giorni ago | 0

Answered
An error in my code
clear syms x % syms F= atan(x); t5= taylor(F,x,'order',5); t7= taylor(F,x,'order',7); fplot(x^3/3+x,[-pi pi],'b') hold o...

14 giorni ago | 2

Answered
I do some revisions to my equation but I still got no answer. It says that there is no enough input argument. Can someone please help me?
x0=[150;150;150;150;150;150;150]; % x = 1:7; % give input vector to fucntion sol=fsolve(@rle,x0) % call the function using fu...

14 giorni ago | 0

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Answered
Pcolor Plot returning error Color data input must be a matrix.
h = pcolor(X1, Y1, z); % use X1, Y1 instead of x1 , y1, z must be 21x26 matrix

15 giorni ago | 0

Answered
how to plot solution of ODE eqution with out using fplot ?
% this code is used to show how to use ode in matlab, via a simple problem % for serios RC circuit with DC supply clc;clear a...

17 giorni ago | 1

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Answered
How can I store the whole diagonal and not only the first element (For loop)
% Part 3.1: Diagonal %A rng('default') r2 = randi(100,3,3); % Creating a 3x3 matrix, with random values from 1 to 100 %B ...

17 giorni ago | 0

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Answered
Why is ySol(t) = Dsolve(ode,cond) wrong? What should it be instead?
y=eval(ySol(t))% Use ySol(t) to evaluate

17 giorni ago | 0

Answered
Having trouble writing a multiple gravitational physics simulation code, as every planet effects one another.
a(q,:)=(sum(F(q:(q+o-1),:)))./mass(q); %Calculate acceleration of each planet v(q,:)=v(q,:)+a(q,:)*ts; %calula...

17 giorni ago | 0

Answered
Trouble graphing this non-linear function
x = 1:100; y = ((factorial(x)).^(1./x))./x; % use element wise division fplot(y,[0 100]) % no space between function and par...

17 giorni ago | 0

Answered
I am trying to a series generated from complex function but it gives to me an error.
clear; clc; syms k Delta=0; chi=0; theta=0; alpha=5; phi=0; bn=exp(-0.5*alpha^2)*(alpha^k)/sqrt(gamma(k+1)); bn1=exp(-0...

24 giorni ago | 0

Answered
using for loops to calculate compound interest with yearly contributions
N=17804; P=1000; C=1000; r=(10/100); I = 1; while P<=N y(I)=(P*(1+r)); % use an index for desired amount, P=y(I)...

29 giorni ago | 0

Answered
Semilogx function giving a linear scale
S = [1e-2 1e-1 1 10 100 1000 1e4]; % Remdesivir concentration, in uM Km = 0.5; % Equilibrium constant, in uM Vmax = 0.82; % ma...

29 giorni ago | 0

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Answered
Need help with syntax and how to use sigma in matlab
clear close all Z1=500 Z2=50 Z3=500 u=1 tau1=(2*Z2)/(Z1+Z2) tau2=(2*Z1)/(Z1+Z2) tau3=(2*Z3)/(Z3+Z2) p1=(Z2-Z1)/(Z2+Z1...

circa un mese ago | 1

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Answered
Unable to perform assignment because the size of the left side is 1-by-2 and the size of the right side is 2-by-2. (Line 32)
pp=@(t,x)[.23*x(1)-.0133*x(1)*x(2); -.4*x(2)+.0004*x(1)*x(2)] [t,y]=rk4sys(pp,[0,65],[550,20],0.3) figure(1) plot(t,y(:,1),...

circa un mese ago | 1

Answered
How to skip a data set in the legend of a plot?
clear; clc; clf; close all; x1 = [0.015 0.020 0.050 0.100 0.200 0.300 0.400 0.500]; y1 = [5.518E-11 7.215E-11 1.832E-10 ...

circa un mese ago | 1

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Answered
how to put for loop value into a vector
k = 0.168:0.168:1.68 ; for x=1:length(k) if k(x)>=0.03 && k(x)<=0.06 h(x)=1.437*k(x)^(-0.279); elseif k(x)>=0.07 && k(x)<...

circa un mese ago | 0

Answered
fplot invalid parameter error
m=100; k1=1500; k2=2500; k3=700; wb=4.4; Y=0.05; w1=sqrt(k1/m); w2=sqrt(k2/m); w3=sqrt(k3/m); r1=wb/w1; r2=wb/w2; r...

circa un mese ago | 1

Answered
Error with the command Geoplot
lat=cell2mat(A.Latitud);% if Latitud is the header name of column. Please check this. There Was extra parenthesis in my pr...

circa un mese ago | 0

Answered
Multiplying f(x) with f(-x)
cof = [1 15 7 2] syms x F(x) F = (cof(1)*x.^3+cof(2)*x.^2+cof(3)*x+cof(4)) FF = subs(F,x,-x) Fx = F.*FF % resulting produc...

circa un mese ago | 0

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Answered
Discontinuous display in Simulink Scope
Select the plot type as Auto in scope block. This plots the graph as continuous signals instead of discrete ones which you have...

circa un mese ago | 0

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