Azzera filtri
Azzera filtri

solving complex matrix with symbolic variables

4 visualizzazioni (ultimi 30 giorni)
hello, I am trying to solve a complex matrix with symbols, but it returns''Empty sym: 0-by-1''. I would like to know why this happened and how could I solve this problem. Thank you.
  1 Commento
ZENONG
ZENONG il 22 Giu 2023
Hi, I updated my code, and it retured values, but I believe there still are some errors, maybe the ''theta'' and ''abs'' variables?

Accedi per commentare.

Risposta accettata

Vishnu
Vishnu il 22 Giu 2023
Hi Zenong,
From the code, it seems that you are trying to solve the complex matrix equations using symbolic variables.However, the issue is that the variables used for 'VI' and 'Vscl' are not symbolic variables, and this is causing the error "Empty sym: 0-by-1".
To solve this issue, the you need to define symbolic variables 'p1', 'q1', 'p2', 'q2', 'p3', 'q3', 'p4' and 'q4' using 'syms' function.
syms a b c d e f g h k p1 p2 p3 p4 q1 q2 q3 q4
Here is the modified code:
syms a b c d e f g h k real %defining symbolic variables
z1=-30j;
z2=0.08+0.40j;
z3=-35j;
z4=0.10+0.50j;
z5=0.10+0.50j;
z6=-25j;
z7=0.30j;
p1=a;
p2=0.55;
p3=0.30;
p4=0.50;
q1=1j*b;
q2=0.15j;
q3=0.201j;
q4=1j*c;
e1=1.05;
e2=d;
e3=e;
e4=f;
f1=0j;
f2=1j*g;
f3=1j*h;
f4=1j*k;
y11=1/z1+1/z2+1/z5;
y12=(-1)*1/z2;
y13=(-1)*1/z5;
y14=0;
y21=y12;
y22=1/z2+1/z4+1/z3;
y23=(-1)*1/z4;
y24=0;
y31=y13;
y32=y23;
y33=1/z6+1/z7+1/z5+1/z4;
y34=0;
y41=y14;
y42=y24;
y43=y34;
y44=1/z7;
Y=[y11,y12,y13,y14;
y21,y22,y23,y24;
y31,y32,y33,y34;
y41,y42,y43,y44];
conjY=conj(Y); %conjugate Y
V=[e1+f1;e2+f2;e3+f3;e4+f4];
format shortG
conjY=round(conjY,2,'significant') %conjugate Y
Vscl=diag(V) %scalar matrix V
conjV=conj(V) %conjugate V
%Defining symbolic variables
syms a b c d e f g h k p1 p2 p3 p4 q1 q2 q3 q4
[a,b,c,d,e,f,g,h,k] = solve([p1+q1;p2+q2;p3+q3;p4+q4]==Vscl*conjY*conjV,[a,b,c,d,e,f,g,h,k]);

Più risposte (2)

MANIK
MANIK il 22 Giu 2023
Modificato: MANIK il 22 Giu 2023
As per my understanding, you're trying to solve a complex matrix equation in MATLAB
Well, I was going through your code, it is all correct. But, here you're trying to solve a problem, which contains 4 equations and 9 variables which is not possible. That's why you're getting an error here.

Torsten
Torsten il 22 Giu 2023
syms a b c d e f g h k real
z1=-30j;
z2=0.08+0.40j;
z3=-35j;
z4=0.10+0.50j;
z5=0.10+0.50j;
z6=-25j;
z7=0.30j;
p1=a;
p2=-0.55;
p3=-0.30;
p4=0.50;
q1=1j*b;
q2=-0.15j;
q3=-0.20j;
q4=1j*c;
e1=1.05;
e2=d;
e3=e;
e4=f;
f1=0j;
f2=1j*g;
f3=1j*h;
f4=1j*k;
y11=1/z1+1/z2+1/z5;
y12=(-1)*1/z2;
y13=(-1)*1/z5;
y14=0;
y21=y12;
y22=1/z2+1/z4+1/z3;
y23=(-1)*1/z4;
y24=0;
y31=y13;
y32=y23;
y33=1/z6+1/z7+1/z5+1/z4;
y34=(-1)*1/z7;
y41=y14;
y42=y24;
y43=y34;
y44=1/z7;
theta=f^2+k^2;
abs=1.1^2;
Y=[y11,y12,y13,y14;
y21,y22,y23,y24;
y31,y32,y33,y34;
y41,y42,y43,y44];
conjY=conj(Y);
V=[e1+f1;e2+f2;e3+f3;e4+f4];
format shortG
conjY=round(conjY,2,'significant');
Vscl=diag(V);
conjV=conj(V);
VIt=Vscl*conjY*conjV;
P=simplify([real([p1;p2;p3;p4]);imag([q1;q2;q3;q4]);theta])
P = 
Q=simplify([real(VIt);imag(VIt);abs])
Q = 
sol=vpasolve(P==Q)
sol = struct with fields:
a: [4×1 sym] b: [4×1 sym] c: [4×1 sym] d: [4×1 sym] e: [4×1 sym] f: [4×1 sym] g: [4×1 sym] h: [4×1 sym] k: [4×1 sym]
sol.a
ans = 
sol.b
ans = 
sol.c
ans = 
sol.d
ans = 
sol.e
ans = 
sol.f
ans = 
sol.g
ans = 
sol.h
ans = 
sol.k
ans = 
error = arrayfun(@(i)subs(P-Q,[a b c d e f g h k],[sol.a(i) sol.b(i) sol.c(i) sol.d(i) sol.e(i) sol.f(i) sol.g(i) sol.h(i) sol.k(i)]),1:4,'UniformOutput',0)
error = 1×4 cell array
{9×1 sym} {9×1 sym} {9×1 sym} {9×1 sym}
error{1}
ans = 
error{2}
ans = 
error{3}
ans = 
error{4}
ans = 

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by