Assign array in field struct

class(Sis)

ans =

'struct'

length(Sis)

ans =

82

c=1

2

3

..

82

i want to create new field in struct

i want this:

Sis.b(1)=1;

Sis.b(2)=2;

..

Sis.b(82)=82;

now i want to semplify calculate

c=1:82

c=c'

>> [Sis.b]=c

Insufficient number of outputs from right hand side of equal sign to satisfy assignment.

[Walter Roberson]

i want this:

Sis.b(1)=1;

Sis.b(2)=2;

Your Sis is a 1 x 82 struct. Sis.b(1) by structure expansion would be as if you had written

Sis(1).b, Sis(2).b, Sis(3).b, Sis(4).b, Sis(5).b ... Sis(82).b(1) = 1;
Sis(1).b, Sis(2).b, Sis(3).b, Sis(4).b, Sis(5).b ... Sis(82).b(2) = 2;

which is not what you want. You want the equivalent of

Sis(1).b = 1;
Sis(2).b = 2;
...
Sis(82).b = 82;

[Vilém Frynta]

oh, i misunderstood. thanks

[Luca Re]

already fixed thanks

Answer 1

[Paul]

Example data

Sis(1).a = 1;
Sis(2).a = 2;
Sis(3).a = 3;
c = [30 40 50];

Assign elements of c to new field of elements of Sis

temp = num2cell(c);
[Sis.b] = temp{:};
Sis.b

ans = 30

ans = 40

ans = 50

Or in one line

clear
Sis(1).a = 1;
Sis(2).a = 2;
Sis(3).a = 3;
c = [30 40 50];

[Sis.b] = table2struct(table(c')).Var1;
Sis.b

ans = 30

ans = 40

ans = 50

[Luca Re]

thanks but in table2struct(table(c')).Var1

what's ".Var1" ? where i find documentation

[Walter Roberson]

When you use table() and pass in an expression (instead of a variable name) then table() automatically uses 'Var' followed by the column number as the name of the variable. So for example table([10;20]; [30;40]) would produce a 2 x 2 table with variables 'Var1' and 'Var2'

[Luca Re]

thanks

Answer 2

[Vilém Frynta]

Sis = struct();
Sis.b = 1:82'

Sis = struct with fields:
    b: [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 … ]

Sis.b(1)

ans = 1

Sis.b(10)

ans = 10

Hope this helps.

[Luca Re]

>> Sis.b = 1:82'

Scalar structure required for this assignment.