Kindly help me understand this code, it is a user defined function for multiplying two polynomials

17 visualizzazioni (ultimi 30 giorni)
User-defined function:
p1 = [2 5 3];
p2 = [4 0 5 8 12];
p = polymult(p1,p2)
p = 1×7
8 20 22 41 79 84 36
p_matlab = conv(p1,p2)
p_matlab = 1×7
8 20 22 41 79 84 36
function p = polymult(p1,p2)
%Multiply polynomials
na=length(p1); nb=length(p2);
if nb > na d=p1; p1=p2;
clear b
p2=d; nd=na; na=nb; nb=nd;
end
for k=1:nb
p(k)=0;
for i=1:k
p(k)=p(k)+p1(i)*p2(k+1-i);
end
end
for k=nb+1:na
p(k)=0; for i=k-nb+1:k
p(k)=p(k)+p1(i)*p2(k+1-i);
end
end
for k=na+1:na+nb-1
p(k)=0; for i=k-nb+1:na
p(k)=p(k)+p1(i)*p2(k+1-i);
end
end
end
  1 Commento
John D'Errico
John D'Errico il 25 Ago 2023
Modificato: John D'Errico il 25 Ago 2023
Are you asking why the user written code does the same thing as conv (though poorly written IMHO), for multiplying two polynomials? Are you asking how that godawful code works at all?
Note that a well written code to perform the multiply need use only one set of loops not three separate sets of loops. As well, a well written code would actually have more than one comment line, so as to be self-documenting. I could make a few more points in this. But if you got that code for free, then it is likely worth exactly what you paid for it: nothing.

Accedi per commentare.

Risposta accettata

John D'Errico
John D'Errico il 25 Ago 2023
Modificato: John D'Errico il 25 Ago 2023
I'm sorry, but that code is complete crapola. Better code might look something like that below.
Test it out.
p1 = [2 5 3];
p2 = [4 0 5 8 12];
p12 = polymult(p1,p2)
p12 = 1×7
8 20 22 41 79 84 36
pconv = conv(p1,p2)
pconv = 1×7
8 20 22 41 79 84 36
function pprod = polymult(P1,P2)
% simple polynomial multiply code
n1 = numel(P1); n2 = numel(P2);
% known length of the result
nprod = n1 + n2 - 1;
% pre-allocate final result as all zeros
pprod = zeros(1,nprod);
% single loop to perform the multiply, though it is actually
% an implicit double loop, since a scalar*vector multiply is employed
for i1 = 1:n1
ind = i1+(0:n2-1);
% just multiply every element of P1 with all of the elements of P2,
% and sum them up.
pprod(ind) = pprod(ind) + P1(i1)*P2;
end
end
Note that the explanation of why and how the code works is complete, and inside the code. I would expect that the use of conv would be faster, since conv will be compiled code.
  4 Commenti

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Polynomials in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by