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Subdivide a cell, based on the number of columns, inside a for loop

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Hi! I would like to compact the rows 'char2string1', 'char2string2', ... inside a for loop. How could I do this?
char2string = importdata("char2string.mat");
num_char2string = width(char2string);
Col = 6;
Row = num_char2string/Col;
Row = round(Row,0);
% I would like to compact these rows because they have to depend by 'Col' and 'Row'
char2string_1 = char2string(1,1:Col);
char2string_2 = char2string(1,Col+1:Col*2);
char2string_3 = char2string(1,Col*2+1:Col*3);
char2string_4 = char2string(1,Col*3+1:Col*4);
char2string_5 = char2string(1,Col*4+1:end);
  3 Commenti
Alberto Acri
Alberto Acri il 8 Set 2023
Modificato: Alberto Acri il 8 Set 2023
Hi @Stephen23, I want to get the variables 'char2string_1', 'char2string_2',...,'char2string_#' (as reported in my question) as the end result.
However, in this case the values of 'char2string_#' depend on Col=6. I would like to generalize what I wrote, with a for loop for example, so that I can get a similar result with a different value of Col.
For example, for Col=4 I should get this:
char2string = importdata("char2string.mat");
num_char2string = width(char2string);
Col = 4;
Row = num_char2string/Col;
Row = round(Row,0);
char2string_1 = char2string(1,1:Col);
char2string_2 = char2string(1,Col+1:Col*2);
char2string_3 = char2string(1,Col*2+1:Col*3);
char2string_4 = char2string(1,Col*3+1:Col*4);
char2string_5 = char2string(1,Col*4+1:Col*5);
char2string_6 = char2string(1,Col*5+1:Col*6);
char2string_7 = char2string(1,Col*6+1:Col*7);
In the case of Col=4, the values of 'char2string_#' are 7, while in Col=6 the values of 'char2string_#' are 5.
I would like to compact the rows with 'char2string_#' and get them directly from a for loop for example.
Dyuman Joshi
Dyuman Joshi il 8 Set 2023
How did you obtain the data? Did you get it as output from some code? As @Stephen23 mentions above, storing in that manner is not efficient.
And why do you want to generate Dynamically named variables?

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Risposte (1)

Julian
Julian il 8 Set 2023
Modificato: Julian il 8 Set 2023
I don't know what you exactly want but this could be your answer:
for i = 7:-1:1
char2string_(i) = char2string(1,Col*(i-1)+1:Col*i);
end
I don't know what you want to do, what is supposed to come out and also how useful all this is.

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R2021b

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