ploting Mitagg leffler function

3 visualizzazioni (ultimi 30 giorni)
Erm
Erm il 10 Set 2023
Hello h
How can I plote the Mittage leffler for the function in [0,50], Here is the code but I do not know how to define the function.
I appreciate your help.
alpha=0.5;
beta=1.2;
function E= ML(z,alpha,beta)
plot(E)
end

Risposte (3)

Sulaymon Eshkabilov
Sulaymon Eshkabilov il 10 Set 2023
Follow this approach. Let's say you'd need to plot: f(a, b, t) = a*exp(cos(b*t)) using a nested function.
a = 2.13;
b = 3.5;
t = linspace(-10, 10, 500);
OUTPUT=My_Fun(a, b, t);
function F = My_Fun(a, b, t)
F = a*exp(cos(b*t));
plot(t, F)
end
  5 Commenti
Erm
Erm il 10 Set 2023
E is sum_{k=0}^{infty} z^k/Gamma(alpha*k+beta) and I wrote it as
syms k z alpha beta
E=symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
but still not working
Walter Roberson
Walter Roberson il 10 Set 2023
alpha = sym(0.5);
beta = sym(1.2);
syms k z
E(z) = symsum(z^k/gamma(alpha*k+beta),k,0,Inf)
E(z) = 
t = linspace(-10, 10, 50).';
Y = E(sqrt(sym(t)))
Y = 
y = double(Y);
subplot(2,1,1); plot(t, real(y), 'k-.'); title('real part');
subplot(2,1,2); plot(t, imag(y), 'r:.'); title('imag part')

Accedi per commentare.


Walter Roberson
Walter Roberson il 10 Set 2023

Sulaymon Eshkabilov
Sulaymon Eshkabilov il 10 Set 2023
As shown in one of the matlab exchange, edit this below shown function file using your own input variables, viz. k, z, alpha, beta
a = ?;
b = ?;
c = ?;
x = ?;
OUTPUT=ML_fun(a, b, c, x);
function f=ML_fun(a,b,c,x)
gamma_c=1.0/gamma(c);
f=0; fa=1; j=0;
while norm(fa,1)>=eps
fa=(gamma(c+j)*gamma_c)/gamma(j+1)/gamma(a*j+b) *x.^j;
f=f+fa; j=j+1;
% You can also add: plot(), hold on % see the simulation progress of ML
% fcn
end
% Or here: plot()
end

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