Can anyone explain from the third line till the end of below code..??

1 visualizzazione (ultimi 30 giorni)
a=imread('kmeans.jpg');
imshow(255-rgb2gray(a));
b=reshape(double(255-rgb2gray(a)),[],1);
[idx,c]=kmeans(b,2,'emptyaction','singleton');
Fin_a=reshape(idx,[size(rgb2gray(a))]);
[ind1, ind2]=find(Fin_a(:,:)==2);
[ind3, ind4]=find(Fin_a(:,:)==1);
figure();
imshow(255-rgb2gray(a));
hold on
if(length(ind1)<length(ind3))
scatter(ind2,ind1,'g');
else
scatter(ind4,ind3,'g');a
end
  1 Commento
Thorsten
Thorsten il 14 Apr 2015
Modificato: Thorsten il 14 Apr 2015
Why don't you just run the code line by line and use doc and read what the functions are doing? And then ask again if you can't figure out particular parts/lines.

Accedi per commentare.

Risposte (1)

Chris McComb
Chris McComb il 13 Apr 2015
The third line from the end contains only the word 'else'. This is typical syntax for the if control structure. In the example, if length(ind1)<length(ind3), the program executes
scatter(ind2,ind1,'g');
However, if length(ind1)<length(ind3) is not true, the program will try to execute:
scatter(ind4,ind3,'g');a
and exit with an error, because the line ends with an 'a' character.
  2 Commenti
John D'Errico
John D'Errico il 14 Apr 2015
I think the question was asking for an explanation starting from line 3 until the end, not the third line from the end.

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by