How do I find all odd numbers between 1 and 60 but are divisible by 5?

How do I find all odd numbers between 1 and 60 but are divisible by 5 using the for loop?

[Dyuman Joshi]

Please show what you have attempted yet.

[Samariah]

for i = 1:2:60
  disp(i)
  end 

     1

     3

     5

     7

     9

    11

    13

    15

    17

    19

    21

    23

    25

    27

    29

    31

    33

    35

    37

    39

    41

    43

    45

    47

    49

    51

    53

    55

    57

    59

[Dyuman Joshi]

That's a good start on the for loop, but you are not testing for divisilibility with 5.

You should include that in your code.

[Samariah]

That's the part I got stuck on. How do I do that? Would it be possible if I can get an example?

[Dyuman Joshi]

How would you test for divisibility by 5 via pen and paper?

[Stephen23]

"That's the part I got stuck on. How do I do that?"

Have a think about what it means to for a value to be "divisible by five": (hint: what is the remainder?)

[Samariah]

Well I know the numbers divisble by 5 betwen 1-60 are 5,15,25, and 35. I tried putting disp(i/5) but that didn't work.

[Dyuman Joshi]

"I know the numbers divisble by 5 ..."

How do you know that? What criteria did you apply to know that?

Take a look at the hint Stephen23 has provided above.

[Samariah]

Well I know that the last number has to end with 5 in order for it to be divisible by 5.

[Torsten]

Odd means: when divided by 2, it gives remainder 1.

Divisible by 5 means: when divided by 5, it gives remainder 0.

Now think about how to use "mod":

https://uk.mathworks.com/help/matlab/ref/mod.html

[Samariah]

mod(60, 5) this gave me 0 but how to I incorporate this into my for loop?

[Torsten]

This is almost a solution. More hints are not possible.

for i = 1:60
  if mod(...) == 1 && mod(...) == 0
    disp(i)
  end
end

or shorter

X = 1:60;
X = X(mod(...) == 1 & mod(...) == 0)

Answer 1

[Walter Roberson]

hint:

for i = 1 : 60
    r7 = remainder7(i);
    if r7 == 0; disp(i); end
end

     7

    14

    21

    28

    35

    42

    49

    56

function v = remainder7(v)
  while v >= 7
      v = v - 7;
  end
end