Transforming a row (inside a matrix) with equal numbers into a row with only one number

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I have amatrix of the following type:
in = [228 228 228
231 231 231
183 183 183
157 157 157
168 168 168];
I need to know if the 3 columns of each row are equal and, if they are, get an Rx1 matrix at the end:
out = [228; 231; 183; 157; 168];
If they are not, keep the initial matrix Rx3 ('in' matrix) and tell me in which row the values of the three columns are not the same.
in_new = [228 228 228
231 231 231
183 200 183
157 157 157
168 168 200];
out_new = [3;5];

Risposta accettata

Dyuman Joshi
Dyuman Joshi il 1 Nov 2023
Modificato: Dyuman Joshi il 1 Nov 2023
in1 = [228 228 228
231 231 231
183 183 183
157 157 157
168 168 168];
[a1, b1] = transform(in1)
a1 = 5×1
228 231 183 157 168
b1 = []
in2 = [228 228 228
231 231 231
183 200 183
157 157 157
168 168 200];
[a2, b2] = transform(in2)
a2 = 5×3
228 228 228 231 231 231 183 200 183 157 157 157 168 168 200
b2 = 2×1
3 5
function [out, out_new] = transform(in)
idx = all(~diff(in, [], 2), 2);
if all(idx)
out = in(:,1);
out_new = [];
else
out = in;
out_new = find(~idx);
end
end

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R2021b

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