identifying and isolating consecutive numbers

I found the following questions in Matlab which is similar to mine

I have a vector, for example, A= [1 2 3 4 14 15 23 24 25 ]

and I want a code that will identify regions of consecutive numbers and separate them into their own array. ie, a code that will split A into

B = [1 2 3 4] C = [14 15] D = [23 24 25]

I would like this code to be able to work on a matrix A of variable length. Any suggestions?

..................I tryed an answer that worked in the first place but then was giviing me an error. The answer and the error are below

MATLAB ANSWER:

A= [1 2 3 4 14 15 23 24 25 ]

A = 1x9

1 2 3 4 14 15 23 24 25

assert(size(A,1)==1 && isa(A,'double'));
p=find(diff(A)>1);
ind=[A(1),A(p+1);A(p),A(end)]

ind = 2x3

1 14 23 4 15 25

% ind =

% 1 14 23

% 4 15 25

ERROR

Operands to the logical AND (&&) and OR (||) operators must be convertible to

logical scalar values. Use the ANY or ALL functions to reduce operands to logical

scalar values.

...

What could I do to rectify please? Thanks

[Walter Roberson]

That code is not producing that error?

Answer 1

[Matt J]

code that will split A into B = [1 2 3 4] C = [14 15] D = [23 24 25]

It would be a bad idea to split A into separate variables, but you can split it in cell array form as follows:

A= [1 2 3 4 14 15 23 24 25 ];
D=find(  diff([A,inf])~=1   );

Asplit=mat2cell(A,1,[D(1), diff(D) ] ) ;  %the final result

Asplit{:}

ans = 1×4

1 2 3 4

ans = 1×2

14 15

ans = 1×3

23 24 25

[Dyuman Joshi]

A similar approach -

A = [1 2 3 4 14 15 23 24 25];

idx = [find(diff(A)~=1) numel(A)];
out = mat2cell(A, 1, [idx(1) diff(idx)])

out = 1x3 cell array
    {[1 2 3 4]}    {[14 15]}    {[23 24 25]}