The Tsunami model has need to fixed this problem

2 visualizzazioni (ultimi 30 giorni)
aoming
aoming il 7 Apr 2024
Commentato: aoming il 8 Apr 2024
hi,
I found that the "https://ww2.mathworks.cn/help/symbolic/solve-a-partial-differential-equation-tsunami-simulation.html#d126e37561", it has the problem that soliton = @(x,t) A.*sech(sqrt(3/4*g*A/H)*(x/c2+t)).^2; ,but it not Conservation of Dimensions . I think that it should be soliton = @(x,t) A.*sech(sqrt(3/4*g*A/H^2)*(x/c2+t)).^2. And I want to confirm that. Thank you!
  2 Commenti
Torsten
Torsten il 7 Apr 2024
The unit of
sqrt(3/4*g*A/H^2)
is sqrt(m)/s. I doubt this can be correct.
aoming
aoming il 8 Apr 2024
Thanks! thank you.But I actually have an another problem,
the code :S = fft(soliton(-0.8*TimeScale*c2, linspace(0,TimeScale,2*(Nt/2)-1)))';
S = repmat(S,1,Nx);
I would like to ask where the initial position of the waves is? In the -0.8*TimeScale*c2? and why it is minus value?

Accedi per commentare.

Risposte (1)

the cyclist
the cyclist il 7 Apr 2024
Disclaimer: I am not an expert in this!
I was not able to track down the exact (Goring & Reichlan) reference from the documentation, and therefore not the exact formula. But, I did find some related materials.
I'm guessing that you might be being fooled by having seen the formula where kappa is inside sech(), rather than g. Looking over some other reference, it seems to me that
kappa ~ g / H
which is where the "missing" dimension of H is hiding.
Another place that may have fooled you is that in the documentation, A is a dimensionless (divided by H) amplitude.
I hope that helps.
  1 Commento
aoming
aoming il 8 Apr 2024
Thanks,cyclist!
But I actually have an another problem
the code :S = fft(soliton(-0.8*TimeScale*c2, linspace(0,TimeScale,2*(Nt/2)-1)))';
S = repmat(S,1,Nx);
I would like to ask where the initial position of the waves is? In the -0.8*TimeScale*c2? and why it is minus value?or the initial position is in the x_max = L2 + 12;?

Accedi per commentare.

Categorie

Scopri di più su Partial Differential Equation Toolbox in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by