Efficient Vectorization of For Loop
2 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Shreyas Bharadwaj
il 15 Apr 2024
Commentato: Shreyas Bharadwaj
il 16 Apr 2024
Hi,
I have three matrices and C and am trying to compute a fourth matrix Min the following way:
for p = 1:N
for q = 1:N
M(p,q) = 2 * sum(A(:,q) .* conj(B(:,p)) .* C(:,q));
end
end
All matrices are . I am trying to compute this for N = 750 or so and the computation is extremely slow. I cannot find any obvious way to vectorize the code. Any help would be very much appreciated.
Thanks.
0 Commenti
Risposta accettata
Bruno Luong
il 15 Apr 2024
Modificato: Bruno Luong
il 15 Apr 2024
Not tested but the sign reading tell me
M = 2*B' * (A.*C);
4 Commenti
James Tursa
il 15 Apr 2024
Modificato: James Tursa
il 15 Apr 2024
I would guess that having 2*B' at the front will force MATLAB to physically compute the conjugate transpose of B first. However, if you segregate the 2* operation as 2 * (B' * (A.*C)), the B' would not need to be physically formed to do the conjugate transpose matrix multiply since this will be handled by flags passed into the BLAS routine. Maybe a bit faster? E.g.,
A = rand(5000); B = rand(5000); C = rand(5000);
timeit(@()2*B' * (A.*C))
timeit(@()2*(B' * (A.*C)))
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!