I'm using the Reduced Order Flexible Solid in Simulink for my project. To put the question in a more general context, lets say I have n interfaces on the solid and I want to keep m fixed-interface modes then in total I have 6*n + m degrees of freedom. To reconstruct the full solution, I need to know the solutions of the 6*n interface dofs and the m fixed-interface modal dofs. The solutions of the 6*n dofs can be obtained easliy, but those of the m fixed-interface modal dofs can not.
I checked the state outputs from the Reduced Order Flexible Solid and there are 6*n+m-6 state outputs. My questions are:
- What are the 6*n+m-6 states? Are they the non-rigid dofs?
- If so, what eigenvalue analysis routine is used to obtain the rigid modes and the non-rigid modes,and more importantly how are the modes scaled?
Knowning the answers to the above questions would help me reconstruct the solutions of the m fixed-interface modal dofs.
Thank you very much!
Zheng-You Zhang