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Issue with integration using trapz

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Rahul
Rahul il 23 Apr 2024
Commentato: Mathieu NOE il 24 Apr 2024
Hello,
I'm trying to implement integration using trapz. But the resultant quantity after integration is negligibly small and doesn't increment. Am I doing something wrong which is confusing me.
Can you see and advice me the chnages if any.
num=15;
Iq(1)=eps;
for i=2:11
Iq(i)=trapz(X(1:i),X(1:i).*jd0.*(1-(X(1:i)-x0).^2).^num);
end
Here, x0=1
rgds,
rc
  3 Commenti
Torsten
Torsten il 23 Apr 2024
To avoid the loop, you can use "cumtrapz" instead of "trapz".
Mathieu NOE
Mathieu NOE il 24 Apr 2024
problem solved ?

Accedi per commentare.

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R2023a

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