Azzera filtri
Azzera filtri

Data type symfun (code problem)

23 visualizzazioni (ultimi 30 giorni)
Patryk
Patryk il 22 Mag 2024 alle 14:35
Spostato: Torsten il 22 Mag 2024 alle 17:48
the content of the task:
Follow these steps to obtain expressions for the critical values ​​of f(x)=x^(3/5)*(4-x)^(1/3):
  1. Define the symbolic function f(x) corresponding to the above formula.
  2. Use the diff function to differentiate f(x) and define the symbolic function df(x).
  3. Use the numden function to obtain symbolic expressions for the numerator and denominator of df(x) and store them in the variables n and d, respectively.
  4. Use the solve function to solve the equations n(x)=0 and d(x)=0. Assign them to the nzeros and zeroros variables respectively.
I have a problem, for this task:
Use the solve function to solve the equations n(x) = 0 and d(x)=0.
Here is my code:
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x));
nzeros = solve(n == 0);
dzeros = solve(d == 0);
%%%%%%% Kod rysujący jest poniżej %%%%%%%%
figure; hold on; grid on;
fplot(f(x),'LineWidth',2);
fplot(df(x),'LineWidth',2);
ylim([-6,6]);
legend('$f(x)$','$f''(x)$','Interpreter','latex','FontSize',14);
Assign them to the "nzeros" and "dzeros" I can't write lines 5 and lines 6 of the code correctly
Code error:
Variable n must be of data type symfun. It is currently of type sym. Check where the variable is assigned a value.
I tried replacing the code like this:
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x));
nzeros = solve(symfun(n,x) == 0);
dzeros = solve(symfun(d,x) == 0);
%%%%%%% Kod rysujący jest poniżej %%%%%%%%
figure; hold on; grid on;
fplot(f(x),'LineWidth',2);
fplot(df(x),'LineWidth',2);
ylim([-6,6]);
legend('$f(x)$','$f''(x)$','Interpreter','latex','FontSize',14);
However, the same error message keeps popping up.
Can anyone help?

Risposte (2)

Torsten
Torsten il 22 Mag 2024 alle 14:43
If your MATLAB release throws an error (R2024a does not as you can see above), try
[n(x) d(x)] = numden(df(x))
instead of
[n d] = numden(df(x))
  1 Commento
Patryk
Patryk il 22 Mag 2024 alle 14:51
Spostato: Torsten il 22 Mag 2024 alle 17:48
replacing [n d] = numden(df(x)) with [n(x) d(x)] = numden(df(x)) helped! Thank you very much :)

Accedi per commentare.


Paul
Paul il 22 Mag 2024 alle 14:44
Hi Patryk,
Works o.k. here. What version of Matlab are you using?
syms x
f(x) = x^(3/5) * (4 - x)^(1/3);
df(x) = diff(f(x));
[n d] = numden(df(x))
n = 
d = 
nzeros = solve(n == 0)
nzeros = 
dzeros = solve(d == 0)
dzeros = 
  1 Commento
Patryk
Patryk il 22 Mag 2024 alle 14:49
Spostato: Torsten il 22 Mag 2024 alle 17:48
I use Matlab online

Accedi per commentare.

Prodotti


Release

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by