任意の2次元座標デー​タから楕円フィッティ​ングをする方法

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kyuu
kyuu il 16 Giu 2024
Risposto: Atsushi Ueno il 16 Giu 2024
お疲れ様です。
早速ですが、添付した点群の2次元座標を1つの楕円に近似したいです。
どうぞ宜しくお願い致します。

Risposte (1)

Atsushi Ueno
Atsushi Ueno il 16 Giu 2024
T = readtable("https://jp.mathworks.com/matlabcentral/answers/uploaded_files/1716431/1%E5%88%97%E7%9B%AE%E3%81%8C%EF%BD%98%E5%BA%A7%E6%A8%99%E3%80%812%E5%88%97%E7%9B%AE%E3%81%8C%EF%BD%99%E5%BA%A7%E6%A8%99%E3%81%A7%E3%81%99.txt");
websave("fit_ellipse.zip", "https://jp.mathworks.com/matlabcentral/mlc-downloads/downloads/submissions/3215/versions/1/download/zip");
unzip("fit_ellipse.zip");
fit_ellipse(T.Var1, T.Var2, axes) % fit_ellipse - finds the best fit to an ellipse for the given set of points.
ans = struct with fields:
a: 59.9916 b: 51.1777 phi: -0.3650 X0: 1.4093e+03 Y0: 815.7096 X0_in: 1.0253e+03 Y0_in: 1.2650e+03 long_axis: 119.9831 short_axis: 102.3555 status: ''
hold on;
scatter(T.Var1, T.Var2, 5);

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