equate the parameters of two equations in symbolic

Hello,

I have two equations, one with known parameters and one with unknown. I would like to ask for a simple way to solve the system that equates the parameters for the two equations

e.g.
eq. 1 = (a2 - a1 - a3 + 1)*x1 + (2*a1 - a2 - 3)*x2 + (3 - a1)*x3
eq. 2 = 0.957*x1 - 0.253*x2 + 0.119*x3

Of course in this simple case it is easy to see that a1=2.043, a2=1.339 and a3=0.177.

One manual way that I have found to work is to create two sym vectors that v1 and v2 that contain the parameters of x1,x2 and x3 and then use the solve function

    p=solve(y==b)

However this method solves the solution into a structure p.a1, p.a2 and p.a3 which is not convient (I would like to have it a vector) And second I have to manually create the sym vectors v1 and v2 which again is not convenient when I have to repeat the same thing for different equations of different orders.

Any ideas to work around this problem?

thank you in advance

Answer 1

[Star Strider]

You can easily create the vector yourself in the format you choose from these results:

syms a1 a2 a3 x1 x2 x3
eq1 = (a2 - a1 - a3 + 1)*x1 + (2*a1 - a2 - 3)*x2 + (3 - a1)*x3;
eq2 = 0.957*x1 - 0.253*x2 + 0.119*x3;

[C1,T] = coeffs(eq1, [x1, x2, x3]);
[C2,T] = coeffs(eq2, [x1, x2, x3]);

[a1, a2, a3] = solve(C1 == C2, [a1, a2, a3])

producing:

a1 =

2881/1000

a2 =

603/200

a3 =

177/1000

Answer 2

[Elric]

Hi Star Strider, the coeffs function was what I was looking for!

Thank you!

[Star Strider]

My pleasure!