Creating a 3-dim matrix from an array and a 2-dim matrices array

1 visualizzazione (ultimi 30 giorni)
I am trying to create a 3-dimensional matrix (e.g. 80 x 300 x 350) from an array (dim 80) and an array of 80 300 x 350 matrices. The second dimension in matrices may vary, so it needs to be padded by 0.
Any hint is welcome.
I have tried this:
for i=1:80
res(i,:,:)=cell2mat(s1(i));
end
and got this:
Subscripted assignment dimension mismatch.
Thank you
  2 Commenti
James Tursa
James Tursa il 22 Apr 2015
If you are using the 300 x 350 slices downstream in your code, you might consider making those the first two dimensions of your 3D matrix so the slices are contiguous in memory. E.g., a 300 x 350 x 80 array.
Valentina Baljak
Valentina Baljak il 22 Apr 2015
thanks for the hint, James, might be useful in the future

Accedi per commentare.

Risposta accettata

Sean de Wolski
Sean de Wolski il 22 Apr 2015
Close! but using :,: means that it must fill the whole thing, not pad with zeros. Instead, only fill to the size:
for i=1:80
sii = cell2mat(s1(i));
res(i,1:size(sii,1),1:size(sii,2)) = permute(sii,[3 1 2]); % permute to write orientation
end
  1 Commento
Valentina Baljak
Valentina Baljak il 22 Apr 2015
Thank you, that looks like shorter solution. In a meanwhile, I have tried more direct approach, using the coder logic, I guess.
%zero 3D matrix, placeholder predict=zeros(80, 300, 350);
for i=1:80 temp=cell2mat(s1(i)); dims=size(temp); d=dims(2); for j=1:300 for k=1:d predict(i,j,k)=temp(j,k); end end end
and it works well enough.

Accedi per commentare.

Più risposte (0)

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by