2D or 3D from CST to matlab
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koorosh dastan
il 27 Lug 2024
Commentato: koorosh dastan
il 5 Ago 2024
i work withh pattern function in matlab but i can get the result and only get err i dont know i can use it or not?
i get text from cst like it for 2D
Theta [deg.] Phi [deg.] Abs(Grlz)[dBi ] Abs(Theta)[dBi ] Phase(Theta)[deg.] Abs(Phi )[dBi ] Phase(Phi )[deg.] Ax.Ratio[dB ]
------------------------------------------------------------------------------------------------------------------------------------------------------
-180.000 90.000 -9.255e+00 -1.298e+01 149.214 -1.165e+01 26.420 5.450e+00
-179.900 90.000 -9.239e+00 -1.295e+01 148.947 -1.165e+01 26.368 5.407e+00
-179.800 90.000 -9.224e+00 -1.292e+01 148.681 -1.164e+01 26.315 5.364e+00
-179.700 90.000 -9.208e+00 -1.289e+01 148.418 -1.163e+01 26.263 5.321e+00
.
.
.
179.600 90.000 -9.319e+00 -1.309e+01 150.304 -1.168e+01 26.638 5.627e+00
179.700 90.000 -9.303e+00 -1.306e+01 150.029 -1.168e+01 26.584 5.582e+00
179.800 90.000 -9.287e+00 -1.303e+01 149.755 -1.167e+01 26.530 5.537e+00
179.900 90.000 -9.271e+00 -1.300e+01 149.484 -1.166e+01 26.477 5.493e+00
in above table i only use first three column which means i like to have pattern in constant phi with various theta
in cst i get this pattern and i want get it in matlab

or about 3d
Theta [deg.] Phi [deg.] Abs(Grlz)[dBi ] Abs(Theta)[dBi ] Phase(Theta)[deg.] Abs(Phi )[dBi ] Phase(Phi )[deg.] Ax.Ratio[dB ]
------------------------------------------------------------------------------------------------------------------------------------------------------
-180.000 -90.000 -9.255e+00 -1.298e+01 329.214 -1.165e+01 206.420 5.450e+00
-175.000 -90.000 -1.014e+01 -1.456e+01 345.709 -1.209e+01 209.583 8.372e+00
-170.000 -90.000 -1.106e+01 -1.607e+01 10.515 -1.271e+01 214.066 1.431e+01
.
.
.
170.000 -85.000 -8.273e+00 -1.118e+01 315.069 -1.139e+01 209.010 2.476e+00
175.000 -85.000 -8.594e+00 -1.155e+01 323.022 -1.166e+01 209.504 3.672e+00
.
.
-180.000 -80.000 -9.255e+00 -1.209e+01 338.042 -1.245e+01 214.316 5.450e+00
-175.000 -80.000 -1.012e+01 -1.327e+01 353.629 -1.299e+01 213.416 8.835e+00
-170.000 -80.000 -1.082e+01 -1.409e+01 16.458 -1.358e+01 212.867 1.684e+01
.
.
160.000 90.000 -1.153e+01 -1.477e+01 248.847 -1.431e+01 48.753 1.504e+01
165.000 90.000 -1.162e+01 -1.622e+01 221.795 -1.347e+01 40.323 3.825e+01
170.000 90.000 -1.106e+01 -1.607e+01 190.515 -1.271e+01 34.066 1.431e+01
175.000 90.000 -1.014e+01 -1.456e+01 165.709 -1.209e+01 29.583 8.372e+00
is it posssible to get them from matlab with patten func or other way
3 Commenti
Harald
il 31 Lug 2024
When running this suggested code, I get the error message
Error using pattern
Too many input arguments.
Umar
il 31 Lug 2024
Hi @Harald,
To resolve this error, I will make ensure that you are passing the correct number of arguments to the pattern function. Thanks for your contribution and helping out.
Risposta accettata
Harald
il 29 Lug 2024
Hi,
for 2D, I would recommend using polarplot:
polarplot(data(:,1), data(:,3))
If you want to separate by Phi, you can use logical indexing to extract the desired data, e.g.
selected = data(:,2) == 90;
polarplot(data(selected,1), data(selected,3))
and then use a loop.
For 3D, I am not aware of an out-of-the-box function. There have been questions around this with different answers, e.g.
Also, you may find File Exchange submissions like these to be helpful:
Best wishes,
Harald
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