Understanding AIC Values for Best Model

5 visualizzazioni (ultimi 30 giorni)
Hello, I am trying to understand how to interpret my AIC outputs for three comparison models. I computed the AIC values using either the cumulative negative log likelihoods (nLL) or cumulative deviance for each model.
In my code, how I assess the two AIC values are as follows:
AIC_nLL = -2 * (cum_nLL) + 4; %4 because it is 2k and I have 2 free parameters in each model
AIC_dev = cum_dev + 4; %4 because it is 2k and I have 2 free parameters in each model
For AIC_nLL I get negative results, (i.e., -15585.2; -15821.7; -35015.2 ) and for AIC_dev I get positive results (i.e., 1.57E+04 ; 1.59E+04; 3.51E+04 ).
While the actual positve/negative values aren't relevant, the decision for which model is best differs between the two calculations, as for AIC_nLL it suggests Model 3 is best and with AIC_dev it suggests Model 1/2 are best.
I have already gone through to double check that my cum_nLL calclulations and cum_deviance calculations are correct. I'm not sure how to move forward with interpreting my results.

Risposta accettata

William Rose
William Rose il 25 Ott 2024
@Alyssa,
Those negative AICs should be positive.
Simple interpretation is to take the model with the lowest (positive) AIC.
  1 Commento
William Rose
William Rose il 25 Ott 2024
@Alyssa, since you took the negative log likelihood, you don't wan't to multiply by -1. That is why you got negative AIC values when you should have had positive.
So both ways of calculating AIC indicate models 1 and 2 are a lot better than model 3.

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by