MLS(moving least squares) algorithm problem... help me!!!

24 visualizzazioni (ultimi 30 giorni)
종영
종영 il 7 Nov 2024 alle 11:34
Modificato: William Rose il 7 Nov 2024 alle 20:55
During MLS, it was conducted as follows. I'm curious about this, I designated weighting for five adjacent points for one point, but I don't know how I can express it diagonally for 100 points as shown in the picture.
I don't know if the code just expressed this as sum or not.
The result value also doesn't come up with an MLS... Help!
clc; clear all; close all
%% give the nodes
x = linspace(0, 1, 100);
y = sin(2 * pi * x) + 0.5 * cos(6 * pi * x + pi / 4) ;
% y_noisy = y;
y_noisy = awgn(y,20);
figure(1)
plot(x,y)
hold on
plot(x,y_noisy,'.r')
%% basis function
ps = [ones(1,length(x)) ;x ;y;x.^2 ; (x.*y);y.^2].';
%% cubic spline function
distances = NaN(length(x), 5);
% weighting = zeros(size(relative_d));
for i = 1 : length(x)
point_index = i;
xi = x(point_index);
yi = y_noisy(point_index);
if point_index == 1
d = sqrt((x(point_index+1:point_index+5) - xi).^2 + (y_noisy(point_index+1:point_index+5) - yi).^2);
distances(i, 1:length(d)) = d;
elseif point_index == 2
distances1 = sqrt((x(point_index-1) - xi).^2 + (y_noisy(point_index-1) - yi).^2);
distances2 = sqrt((x(point_index+1:point_index+4) - xi).^2 + (y_noisy(point_index+1:point_index+4) - yi).^2);
d = [distances1, distances2];
distances(i, 1:length(d)) = d;
elseif point_index > 2 && point_index < length(x) - 2
distances1 = sqrt((x(point_index-2:point_index-1) - xi).^2 + (y_noisy(point_index-2:point_index-1) - yi).^2);
distances2 = sqrt((x(point_index+1:point_index+3) - xi).^2 + (y_noisy(point_index+1:point_index+3) - yi).^2);
d = [distances1, distances2];
distances(i, 1:length(d)) = d;
elseif point_index == length(x) - 2
distances1 = sqrt((x(point_index-3:point_index-1) - xi).^2 + (y_noisy(point_index-3:point_index-1) - yi).^2);
distances2 = sqrt((x(point_index+1:point_index+2) - xi).^2 + (y_noisy(point_index+1:point_index+2) - yi).^2);
d = [distances1, distances2];
distances(i, 1:length(d)) = d;
elseif point_index == length(x) - 1
distances1 = sqrt((x(point_index-4:point_index-1) - xi).^2 + (y_noisy(point_index-4:point_index-1) - yi).^2);
distances2 = sqrt((x(point_index+1) - xi).^2 + (y_noisy(point_index+1) - yi).^2);
d = [distances1, distances2];
distances(i, 1:length(d)) = d;
elseif point_index == length(x)
d = sqrt((x(point_index-5:point_index-1) - xi).^2 + (y_noisy(point_index-5:point_index-1) - yi).^2);
distances(i, 1:length(d)) = d;
end
dmi = mean(distances, 2); %질문!
% dmi(1:100) = 10;
relative_d(i,:) = abs(distances(i,:))./dmi(i);
for j = 1:5
if relative_d(i,j) < 0.5
weighting(i,j) = 2/3 - 4*relative_d(i,j).^2 + 4*relative_d(i,j).^3;
elseif relative_d(i,j) > 0.5 && relative_d(i,j) < 1
weighting(i,j) = 4/3 - 4*relative_d(i,j) + 4*relative_d(i,j).^2 - (4/3)*relative_d(i,j).^3;
else
weighting(i,j) = 0;
end
end
weight_mean = sum(weighting, 2) /5; % 질문!
weight_fin = diag(weight_mean);
p_x(:,i) = [1; xi; yi; xi.^2; (xi .* yi); yi.^2];
end
A = ps.' * weight_fin * ps;
B = ps.' * weight_fin;
phi= p_x.' * (A^-1 * B) * y_noisy.';
% for i = 1 : 100
% figure(2)
% plot(1:5,weighting(i,:))
% hold on
% end
%% Obtain the matrixed
%
figure(2)
plot(x,y)
hold on
plot(x,y_noisy)
plot(x,phi)
legend('orginal','noise signal','MLS signal')

Risposte (1)

William Rose
William Rose il 7 Nov 2024 alle 20:42
Modificato: William Rose il 7 Nov 2024 alle 20:55
In your comment you refer to "cubic spline function". Cubic splines for smoothing can be done with csaps(). The code below shows spline smoothing with three levels of smoothing: no smoothing (p=1); intermediate smoothing (p=.9999948); max smoothing (p=0).
n=100; % number of data points
x = linspace(0, 1, n);
y = sin(2 * pi * x) + 0.5 * cos(6 * pi * x + pi / 4) ;
yNoisy = awgn(y,10); % add Gaussian white noise, snr=10 dB
figure
subplot(211), plot(x,y,'-k',x,yNoisy,'.k')
legend('No noise','With noise'); grid on
Fit cubic splines to the data, with varying amounts of smoothing:
h=x(2)-x(1); % h=delta x
% p=1//(1+h^3/6); % initial guess for smoothing parameter p
% make p smaller/larger for more/less smoothing
ys1=csaps(x,yNoisy,0,x); % p=0: straight line
p=1/(1+h^3/0.2); % smoothing parameter p
ys2=csaps(x,yNoisy,p,x); % p=smoothing paramater
ys3=csaps(x,yNoisy,1,x); % p=1: cubic spline thorugh every data point
Plot results
subplot(212), plot(x,yNoisy,'.k',x,ys1,'-b',x,ys2,'-g',x,ys3,'-r')
legend('Data','p=0',['p=',num2str(p,'%.7f')],'p=1'); grid on
I realize this does not address why your code doesn't work. But the solution above does get the job done, and it is probably easier than debugging your code.

Categorie

Scopri di più su Smoothing in Help Center e File Exchange

Prodotti

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by