Linear indices from colon operator

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Radek
Radek il 14 Nov 2024
Modificato: Stephen23 il 15 Nov 2024
Any array (let's consider only 2D here) can be indexed using colon operator such
array(p1:p2,p3:p4)
How can one generate list of linear indices (for that particular array) from parameters [p1, p2, p3, p4]?

Risposta accettata

Matt J
Matt J il 14 Nov 2024
[I,J]=ndgrid(p1:p2,p3:p4);
linear=sub2ind(size(array) , I,J);

Più risposte (2)

Steven Lord
Steven Lord il 14 Nov 2024
See sub2ind.
  2 Commenti
Stephen23
Stephen23 il 14 Nov 2024
Modificato: Stephen23 il 15 Nov 2024
Note that in general p1:p2 and p3:p4 when used a indices like that will refer to a rectangular block of that array. So in order to get the linear indices of the entire block you will need to provide SUB2IND with subscript indices for the entire block. One way to achieve this is using NDGRID:
array = randi(9,9,9);
p1 = 3;
p2 = 5;
p3 = 2;
p4 = 5;
[X,Y] = ndgrid(p1:p2,p3:p4);
Z = sub2ind(size(array),X,Y);
array(Z)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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array(p1:p2,p3:p4)
ans = 3×4
4 7 2 6 9 9 6 7 1 2 4 8
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Walter Roberson
Walter Roberson il 14 Nov 2024
sub2ind() processes the indexes in parallel. All of the indices must be the same size (or else scalars)
sub2ind([4 5],1:2,1:3)
Error using sub2ind (line 61)
Subscript arguments must be scalars or arrays of the same size.

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Catalytic
Catalytic il 14 Nov 2024
Modificato: Catalytic il 14 Nov 2024
K=createArray(size(array),Fill=sparse(0));
K(p1:p2,p3:p4)=1;
out=find(K); %linear indices
  1 Commento
Matt J
Matt J il 14 Nov 2024
I would probably do instead,
K=createArray(size(array),Fill=sparse(false));
or maybe just use,
K=false(size(array))
depending on the expected size of the output.

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R2021b

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