concatanate arrays upon condition
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Levente Gellért
il 20 Giu 2025
Commentato: Walter Roberson
il 23 Giu 2025
Dear MatLAb Community,
I would like to concatanate selected coloumns of arrays, some of which are empty arrays, and this is varying dataset by dataset.
How can I exclude the empty arrays from concatanation?
Let's say now , distr3 and distr6 are empty but this my vary.
distr = cat(1,distr1(:,ch1),distr2(:,ch2),distr3(:,ch3),distr4(:,ch4),distr5(:,ch5),distr6(:,ch6),distr7(:,ch7),distr8(:,ch8));
Thans for you suggestions
BEst
lg
1 Commento
Risposta accettata
Matt J
il 20 Giu 2025
Modificato: Matt J
il 20 Giu 2025
The way your data is held, as separate enumerated variables, doesn't leave many options. The first thing would be to undo that:
distrCell = arrayfun(@(i)eval("distr"+i),1:8,'uni',0); %should be unnecessary
chCell = arrayfun(@(i)eval("ch"+i),1:8,'uni',0); %should be unnecessary
Then, you can do,
keep=~cellfun('isempty',distrCell);
distrCell=distrCell(keep);
chCell=chCell(keep);
distr=cell2mat( cellfun(@(d,c) d(:,c), distrCell,chCell ,'uni',0 ) )
2 Commenti
Matt J
il 20 Giu 2025
Modificato: Matt J
il 20 Giu 2025
Modify along the following lines:
distr1=17; distr2=5; distr3=68;
distrCell = arrayfun(@(i)evalin('caller',"distr"+i),1:3,'uni',0) %should be unnecessary
Or, even better, recreate the data from scratch, but instead of distr1, distr2,... store the arrays in a distrCell variable directly.
Più risposte (1)
Walter Roberson
il 20 Giu 2025
At least in R2025a, there is no problem in using "," to concatenate empty datasets, as long as they are empty along either the first or second dimension. (There can be problems if they are empty along the third dimension and the sizes of the first and second dimension do not match the existing data.)
A = zeros(5,3);
B = ones(5,0);
C = zeros(5,2);
D = []; size(D)
E = ones(3,0);
F = ones(0,3);
G = ones(10,9,0);
[A,B,C]
[A,D,C]
[A,E,C]
[A,F,C]
[A,G,C]
4 Commenti
Walter Roberson
il 23 Giu 2025
Modificato: Walter Roberson
il 23 Giu 2025
Is the error you recieved due to the fact that you are subscripting an empty array at columns that do not exist?
T1 = randi(9,5,3)
T2 = randi(9,7,4)
T3 = randi(9,4,1)
T4 = randi(9,6,3)
S = @(A,c) A(:,c:c.*(c<=size(A,2)));
%use the auxillary function S to select columns
[S(T1,2); S(T2,2); S(T3,2); S(T4,2)]
%whereas directly indexing might fail
[T1(:,2); T2(:,2); T3(:,2); T4(:,2)]
Walter Roberson
il 23 Giu 2025
Huh, there is a difference between cat(1,A,B) and [A;B] ...
A = zeros(5,1);
B = ones(3,0);
[A;B]
cat(1, A, B)
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