Matrix with Bell Triangle
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I need to reshape a portion of a matrix computed with the values of a bell triangle where n is the number of rows of a matrix. How can I generate a matrix contain the bell values? I mean, as an example, for n= 4 but could be any value:
1
1 2
2 3 5
5 7 10 15
empty space with 0.
6 Commenti
Guillaume
il 22 Mag 2015
How do you represent that triangle as a matrix (which by definition is a rectangle) ?
Millone
il 22 Mag 2015
Titus Edelhofer
il 22 Mag 2015
Hi Millone,
a loop over the rows and using cumsum will do the job ... have you tried this?
Titus
Millone
il 22 Mag 2015
Millone
il 22 Mag 2015
Risposta accettata
Più risposte (3)
Titus Edelhofer
il 22 Mag 2015
O.k., when there is a full solution, I'm happy to share mine as well ;-)
function B = bell(n)
B = zeros(n);
B(1,1) = 1;
for row=2:n
B(row, 1:row) = B(row-1,row-1) + cumsum([0 B(row-1, 1:row-1)]);
end
Titus
Andrei Bobrov
il 22 Mag 2015
n = 5;
a = zeros(n);
a(1) = 1;
for jj = 1:n-1
a(jj+1,1:jj+1) = cumsum(a(jj,[jj,1:jj]),2);
end
Guillaume
il 22 Mag 2015
Assuming you're talking about this, I've tried to come up with a clever way to generate it, but didn't find any (didn't spend too much time on it either). When all else fail, loops always work:
bell = zeros(n);
bell(1) = 1;
for row = 2 : n
bell(row, 1) = bell(row-1, row-1);
for col = 2 : row
bell(row, col) = bell(row, col-1) + bell(row-1, col-1);
end
end
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