Integer conversion without precision loss for literal function inputs
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The function uint64 can take a literal input that is not representable by double and convert without precision loss, like
uint64(7725400999518902274)
Unfortunately, this functionality does not seem to extend to a function with an argument block and type validation.
function test(a)
arguments
a (1,1) uint64
end
disp(a)
end
test(7725400999518902274)
I would have to do
test(uint64(7725400999518902274))
Does anyone know if there is a trick to get this functionality or I am otherwise missing something?
4 Commenti
Dyuman Joshi
il 20 Nov 2025
"The function uint64 can take a literal input that is not representable by double and convert without precision loss"
That is not true, it can do that within [0, 2^64-1]
uint64(123456789012345678901)
uint64(2^64-1)
uint64(2^64+1)
Risposta accettata
Matt J
il 20 Nov 2025
Modificato: Matt J
il 20 Nov 2025
test 7725400999518902274
function test(a)
arguments
a (1,:) string
end
a=eval("uint64("+ a + ")"),
end
8 Commenti
Paul
il 19 Dic 2025 alle 4:02
Is there any reason to prefer command syntax? Function syntax seems to work fine.
test 7725400999518902274
test("7725400999518902274")
function test(a)
arguments
a (1,:) string
end
a=eval("uint64("+ a + ")"),
end
Più risposte (1)
Walter Roberson
il 21 Nov 2025
Does anyone know if there is a trick to get this functionality
There is no way of doing that.
Any way of doing that would have to affect the inputs at parse time. However, arguement blocks do not affect parse time. Arguement blocks apply conversions to whatever input was passed in. By the time the arguement block processing is applied, the parameter has already been parsed as double precision.
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