Solve system of equations

I want to solve 4 equation such that:

a0=F(B1,B2,B3,B4);

a1=F(B1,B2,B3,B4):

k=F(B1,B2,B3,B4);

[Catalytic]

Isn't that 7 equations? And what is F()?

[Walter Roberson]

Are a0, a1, and k intended to be the same? Since they are all F(B1,B2,B3,B4) ?

[T K]

F mean that function of B1,B2,B3,B4

Answer 1

[Walter Roberson]

Examine the second and third equations. The terms - B4*a0 - B2 are the same between the two of them, so you can subtract the two equations from each other. The result is 8*k*B3*a1 - 3*k*B3*a1 = 0. Provided that k, a1, and B3 are not 0, then the k*B3*a1 can be factored out... giving 8 - 3 = 0.

Therefore the equations are inconsistent unless at least one of k, a1, or B3 are 0, in which case the equation would become 8*0 - 3*0 = 0, which is consistent, But having made those two terms 0, the second and third equations become identical.

So the equations are either inconsistent or else they are redundant