Accept 2 numbers from user
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This is my current code. how do i add this part of my algorithm into matlab code
integer :: a, b, c
integer :: abc, a3b3c3
integer :: count
count = 0
count = count + 1
clc
num1 = input('Enter num1 value: ');
num2= input('Enter num2 value: ');
fprintf('Armstrong numbers between %d and %d are: \n',num1 ,num2);
for a = 1 : 9
for b = 0 : 9
for c = 0 : 9
n = a*100 + b*10 + c;
an = a^3 + b^3 + c^3;
if n == an
fprintf('%d, ',an)
end
end
end
end
Risposte (1)
Andrei Bobrov
il 27 Mag 2015
Modificato: Andrei Bobrov
il 27 Mag 2015
a1 = 1 : 9;
b1 = 0 : 9;
c1 = 0 : 9;
num1 = input('Enter num1 value: ');
num2= input('Enter num2 value: ');
[c,b,a] = ndgrid(c1,b1,a1);
n = a*100 + b*10 + c;
an = a^3 + b^3 + c^3;
t1 = n >= num1 & n <= num2;
t2 = an == n;
out = an(t1 & t2);
3 Commenti
Josaiah Ang
il 27 Mag 2015
Josaiah Ang
il 27 Mag 2015
Walter Roberson
il 27 Mag 2015
The calculation for Armstrong numbers depends upon the number of digits. The program is for 3 digit Armstrong numbers only. You are trying to find some 1 digit Armstrong numbers and some 2 digit Armstrong numbers. Your algorithm needs to be changed for that.
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