How do I integrate a differential equation?
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nashyshan
il 1 Giu 2015
Commentato: Walter Roberson
il 2 Giu 2015
Hi, I want to integrate a differential equation dc/dt. Below is the code and the values of the variables.
clear all;
c1=.185;c0=2*10^-6;k3=.1*10^-6;
v1=6;v2=.11;v3=.09*10^-6;
Ca_ER=10*10^-6;Ca_cyto=1.7*10^-6;
p_open3=0.15;c=15*10^-6;
dcdt= (c1*(v1*(p_open3)+v2)*(Ca_ER)-c)-v3*((c)^2)/(c^2+(k3)^2);
I know there is an integral function but I am not sure how to apply for this equation. How do I proceed from here? Please help. The value of initial c, if needed, can be taken as 0.15*10^-6. Also, I need to plot the obtained result versus time. So will get an array of values or just a single value?
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Star Strider
il 1 Giu 2015
Try this:
c1=.185;c0=2E-6;k3=1E-7;
v1=6;v2=.11;v3=9E-8;
Ca_ER=10E-6;Ca_cyto=1.7E-6;
p_open3=0.15;
ci=15E-6;
dcdt = @(t,c) (c1.*(v1.*(p_open3)+v2).*(Ca_ER)-c)-v3.*((c).^2)./(c.^2+(k3).^2);
tspan = linspace(0, 10, 25);
[t,c] = ode45(dcdt, tspan, ci);
figure(1)
plot(t, c)
grid
4 Commenti
Walter Roberson
il 2 Giu 2015
Use Star Strider's code but increase the upper time bound. For example,
tspan = linspace(0, 40, 75);
I do not understand why the wiggles are not visible if an upper time bound of 30 is used, but they are visible if 35 is used and clearly peak near 20.
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