HI, i want to plot x=sin(t*pi) fuction like this picture for t[0:1:24] and x will be 0 when t=17

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Joseph Cheng
Joseph Cheng il 4 Giu 2015
Modificato: Joseph Cheng il 4 Giu 2015
figure out what azzi was doing in the math which would lead you to figure out what to change.
t=0:0.01:24
y=sin(t*pi).*(t<15) + 3*sin(t*pi).*(t>=15)
plot(t,y)

Più risposte (1)

Azzi Abdelmalek
Azzi Abdelmalek il 4 Giu 2015
t=0:0.01:24
y=sin(t*pi).*(t<17)
plot(t,y)
  1 Commento
Image Analyst
Image Analyst il 5 Giu 2015
david's two "Answers" moved here: because they are comments (replies) to Azzi and not "Answers" to his original question at the top of the page.
thank you Mr.AZZI i'm really satisfied with your answer so if I want to change the amplitude at t = 15 like this picture
y=sin(t*pi) for 0<t<15
y=3*sin(t*pi) for t>15
thank you very much . my last question is if i want to change the amplitude of sinus 7 times 0<t<38
first for 0<t<10 y= sin(t*pi)
and for 10<t<15 y=2*sin(t*pi)
and for 15<t<19 y=5*sin(t*pi)
and for 19<t<24 y=sin(t*pi)
and for 24<t<27 y=0
and for 27<t<35 y=4*sin(t*pi)
and for 35<t<38 y=0

Accedi per commentare.

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