How do you read this code?

Can somebody break down how they would read this code?
>> A=[0:2:10];k=2;
>> B=A(mod((1:end)-k-1,end)+1);
I end up with B=A(9 10 0 1 2 3 4 5 6 7)...

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Walter Roberson
Walter Roberson il 11 Giu 2015

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What Walter is trying to say is that, don't post same questions, I believe!

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