Undefined function or method 'fft' for input arguments of type 'sym'.
Mostra commenti meno recenti
Hi Everyone: When I run this script:
syms t
x=-3:.1:3;
for i=1:length(x);
Pin=3*exp(-t^2);
z=x(i);
Eo(i)=int(Pin,t,-inf,z);
Ein(i)=int(Pin,t,-inf,inf);
E(i)=Eo (i)/Ein(i);
Go=1000;
G(i)=Go/(Go-(Go-1)*exp(-E(i)*0.1));
Pin=3*exp(-x(i)^2);
Pout(i)=Pin*G(i);
Poutf=fftshift(fft(Pout,100000));
f=(-100000/2:(100000/2-1)).*1/(0.01*100000);
end
plot(f,abs(Poutf),'-r*')
I face this error:
Undefined function or method 'fft' for input arguments of type 'sym'.
Could anyone help me please?
Risposte (2)
Wayne King
il 28 Nov 2011
0 voti
fft is not overloaded for symbolic inputs. fft() is only for numeric inputs. If you want the Fourier transform of a symbolic input, see fourier
Walter Roberson
il 28 Nov 2011
0 voti
Use E(i) = double(Eo (i)/Ein(i));
Note: it is a waste of time to do the integrations ever iteration. Do the integration with a symbolic upper bound once before the loop, evaluate that with infinity as the upper bound once before the loop to get the constant Ein, and then in your loop subs() your x(i) in to the indefinite integral as the upper bound to get Eo(i).
The ratio will, by the way, come out as (1+erf(x(i))/2
Categorie
Scopri di più su Symbolic Math Toolbox in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!