Who can help me solve this matlab ques?

How to solve this problem by matlab?

Start with number 5, get unknown(I) as the equally space, then I want 20 terms of number. I tried this before>> [5:3:(5+19*3)] Take 3 as the unknown(I)

[Image Analyst]

Can you have a native English speaker look this over. I can't figure out what you want. Let's use x for the spacing instead of 3. So you want to solve for [5, 5+s, 5+2s, 5+19s], but I don't know what to solve for . Nothing is unknown if you specify s. If you specify the value of the last element, 5+19s, then you can solve for s. But as it is worded right now everyone (not just me) is confused.

Answer 1

[Kristin]

Have you tried [5:3:(5+19*3)] in matlab?

If I understand your question correct, it will give you the whanted answer.

   [5:3:(5+19*3)]

ans =

     5     8    11    14    17    20    23    26    29    32    35    38    41    44    47    50    53    56    59    62

[Kent Lam]

Yes I had tried this in Matlab before. But my teacher want the 3 be the unknown(I), this equation isn't what he want. He want the answer be more creative

[Walter Roberson]

You mean creative like

5:unknown(i):(5+19*unknown(i))

or creative like

5 + unknown(i) * (0:19)

[Joseph Cheng]

shouldn't the creativity come from you?

[Kent Lam]

This answer is creative but it cant present in Matlab right? I also tried it

[Walter Roberson]

Which answer are you referring to?

i = 1;
unknown = 3;
5 + unknown(i) * (0:19)

ans =

     5     8    11    14    17    20    23    26    29    32    35    38    41    44    47    50    53    56    59    62

[Kent Lam]

Except this kind of answer, I want the another answer

[Walter Roberson]

i = 1;
unknown = 3;
5:unknown(i):(5+19*unknown(i))

ans =

     5     8    11    14    17    20    23    26    29    32    35    38    41    44    47    50    53    56    59    62

Nothing remarkable there?

Answer 2

[Farzan Farzin]

Is there any one to help me in MATLAB?

[Walter Roberson]

You should create Question asking about your interests.

[Farzan Farzin]

How to implement the mu law in matlab, it means this formula x= (_1,1) and mu= 255 Y(n)= ln(1+mu)x(n)/ln(1+mu).sgn(x(n) but it is not complet formulla if you can solve it please send me your email I should send you the whole file

[Walter Roberson]

https://www.mathworks.com/matlabcentral/answers/425337-mu-law-compressor-function