How to plot a 2D graph using all the for loop values؟

clc,clear
xi=input('The solution gas-oil ratio(Rsb)\n');
yi=input( ' The specific gravity of separator gas\n');
Ti=input('reservoir temperature\n');
pi=input('reservoire pressure\n');
zi=input('API of stock tank\n');
Xi=(.013098*Ti^.282372)-(8.2*10^-6*zi^2.176124);
pb=1091.47*(xi^.081465*yi^-.161488*10^Xi-.740152)^5.35489;

fprintf('%s\n%d\n','pb',pb);

fprintf('%4s%15s%20s\n','pi','Co','D');

    for ni=1000:1000:10000
        n=0;
     pi=n+ni;
     if pi>=pb
       RS=xi;
       Co=(-1433+5*xi+2.902*Ti+1.327*yi+12.61*zi)/(10^5*pi);
     Apo=52.8-0.01*xi;
     for ki=1:100
         Aa=-49.893+85.0149*yi-3.70373*yi*Apo+.0479*yi*Apo^2+2.98914*Apo-0.035688*Apo^2;
         bpo=(xi*yi+4600*zi)/(73.71+(xi*yi/Aa));
     end
     Ci=bpo+(.167+16.181*(10^(-0.0425*bpo)))*(pi/1000)-.01*(.299+263*(10^(-0.0603*bpo)))*(pi/1000)^2;
     zai=Ci-(0.00302+1.505*Ci^-.951)*(Ti-60)^.938+(.0233*(10^-0.0161*Ci))*(Ti-60)^.475;
     fprintf('%4d %15d%20d\n',pi,Co,zai);

     end

    end
  plot(p,Co);

[Amr Hashem]

what is the error you get?

try to attach a sample (image), for better illustration.

[Mostafa Shehab]

it only plot one point not all loop points

[Walter Roberson]

A sample of what you would like the plot to look like would be useful. But you can fix the problem about only plotting one point by making the change I showed in my Answer.

Answer 1

[Walter Roberson]

nvals = 1000:1000:10000;
for nidx = 1 : length(nvals)
  n = nvals(nidx);
  ......
  Co(nidx) = (-1433+5*xi+2.902*Ti+1.327*yi+12.61*zi)/(10^5*pi);
  ...
end

By the way, it is quite confusing for readers when you use "pi" as a variable instead of leaving it as the default constant 3.1415926 (etc)

[Mostafa Shehab]

I'd like to know how get output as vector in for loop in general

[Walter Roberson]

Follow the framework I gave here: create a vector of the input values, loop over the possible indices of the vector, pull out a particular input value from the vector by its index, store the output indexed by your counter.